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Serjik [45]
3 years ago
8

Write the electrons configuration for an atom of an element whose atomic number is 8

Chemistry
1 answer:
Basile [38]3 years ago
6 0
The electron configuration for a atom whose element has a atomic number of 8 (Oxygen) is 2,6
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Write the balanced chemical equation for the Haber-Bosch process, that is, the combination of nitrogen and hydrogen to form ammo
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Name the element described in each of the following:
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The element is Si (Silicon)

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7 0
2 years ago
How do you calculate a wavelength of light emitted when
Novosadov [1.4K]

Answer: Wavelength of light emitted when  the electron in doubly ionized lithium makes a transition  from E12 to E8 is  0.1050\times 10^{-4m

Explanation:

Li:3:1s^22s^1

Li^{2+}:1:1s^1

Using Rydberg's Equation for hydrogen and hydrogen like atom:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant

n_f = Higher energy level  

n_i= Lower energy level

We have:

n_f=8, n_i=12

R_H=1.097\times 10^7 m^{-1}

\frac{1}{\lambda}=1.097\times 10^7 m^{-1}\times \left(\frac{1}{12^2}-\frac{1}{8^2} \right )

\frac{1}{\lambda}=1.097\times 10^7 m^{-1}\times \frac{5}{576}

\frac{1}{\lambda}=9.523\times 10^4 m

\frac{1}{\lambda}=9.523\times 10^4 m

{\lambda}=0.1050\times 10^{-4}m

The wavelength of the photon emitted when the hydrogen atom undergoes a transition is 0.1050\times 10^{-4m

8 0
3 years ago
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