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3 years ago

Zn(s) + 2HCl(aq) mc029-1.jpg H2(g) + ZnCl2(aq) Which product is a substance that is dissolved in solution?

1 answer:

8 0

The product that is dissolved in the solution would be the salt zinc chloride. It is a substance that is soluble in water so it should be dissolved in the solution. Also, from the reaction, the sign (aq) is written. It means that this substance is in aqueous solution.

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There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. Cac

Tanya [424]

Answer:

The equation that gives the overall equilibrium in terms of the equilibrium constants K and Ky is K1 = K^6 * Ky

Explanation:

we have the following balanced reaction:

CaC2 + 2H2O = C2H2 + Ca(OH)2

the value of K for this reaction will be equal to:

K = ([C2H2] * [Ca(OH)2])/([CaC2] * [H2O]^2)

if we multiply the reaction by the value of 6, we have:

6CaC2 + 12H2O = 6C2H2 + 6Ca(OH)2

Again, the value of K for this reaction will be equal to:

K,´ = ([C2H2] ^6 * [Ca(OH)2]^6)/([CaC2]^6 * [H2O]^12) = K^6

For the second reaction:

6C2H2 + 3CO2 + 4H2O = 5CH2CHCO2H

The value of K for this reaction:

K2 = ([CH2CHCO2H]^5)/([C2H2]^6 * [CO2]^3 * [H2O]^4)

we also have:

K1 = ([CH2CHCO2H]^5)/([C2H2]^6 * [CO2]^3 * [H2O]^16)

Thus:

K1 = K^6 * Ky

4 0

3 years ago

Matter is never created or destroyed.

kumpel [21]

I believe it is true!

8 0

3 years ago

Name two metalloids that are semiconductors

guajiro [1.7K]

The Metalloids are:

Boron.

Silicon.

5 0

3 years ago

ANSWER QUICK PLEASE ILL GIVE BRAINLIEST AND 50 POINTS

yawa3891 [41]

Answer:

Single replacement and Zinc Sulfate

the 2nd one is double replacement and potassium nitrate

5 0

2 years ago

Read 2 more answers

The following reaction has an equilibrium constant (Keq) of 1 under standard conditions and can be catalysed by the enzyme aspar

Trava [24]

Answer:

What is the AGⓇ of this reaction? 0.
Which will be favoured - the forward reaction, the reverse reaction, or neither? Neither.
What effect does the presence of the enzyme aspartate transaminase have on the Key value when compared with its value in the absence of enzyme? It does not affect the value of Keq.
If one of the products of reaction 1, oxaloacetate, is removed by converting it to citrate as follows: Reaction 2: oxaloacetate + acetyl-CoA citrate + COASH will the key for Reaction l be changed? No, the Keq does not change.

Explanation:

1. To calculate the delta G of a reaction given the K, we use the following equation:

ΔG°= -RT ln K.

Which gives us 0 when K is 1.

2.None of the reactions is favoured. Given that the K equals 1, the system will try to keep the concentration of both products and reagents the same.

3. A catalyst is a substance that, when added, provides a different and faster mechanism through which a reaction takes place. This only means that the speed at which the equilibrium is attained is reduced, but the enzyme does nothing to alter the difference in energy (ΔG°) of the start and end points of the reaction, which ultimately gives us the value of Keq.

4. The addition of a side reaction does not change the value of Keq for the main reaction. They are both separate ways of making oxaloacetate disappear. While the Keq does not change, keep in mind that the end concentrations will not be the same, for any set of starting concentrations of your substances.

4 0

3 years ago