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Novay_Z [31]
3 years ago
8

No spam or leaks

Physics
2 answers:
Sever21 [200]3 years ago
6 0

Answer:

D

Explanation:

It is better if you start when you are younger to improve when you are older and to strive for a better you.

aalyn [17]3 years ago
4 0

Answer:

bro ODODODODODOD

Explanation:

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You fire a paintball from a paintball gun straight up into the air at 25.0 m/s. What is the ball velocity at the higher point th
iVinArrow [24]

Given :

You fire a paintball from a paintball gun straight up into the air at 25.0 m/s.

To Find :

What is the ball velocity at the higher point that the ball reaches.

Solution :

We know, when ball is moving upward acceleration due to gravity is applied downward.

So, the ball will decelerate and when ball reaches maximum height its velocity will become zero.

Therefore, ball velocity is 0 m/s at maximum height.

Hence, this is the required solution.

5 0
3 years ago
When you have a pot of water on the stove, heat is transferred to the water. Describe the behavior of the water molecules and ho
NikAS [45]
<span>Temperature causes water molecules to move more quickly, because each individual molecule has more energy as it gets hotter (according to Kinetic molecular theory). If you get water hot enough, the molecules move so much that the hydrogen bonds that hold them together start to break and the water becomes a gas ... water vapor. This your answer unless there are choices.</span>
3 0
4 years ago
Read 2 more answers
The launch speed of a projectile is three times the speed it has at its maximum height.what is the elevation angle at launch?
Sphinxa [80]

Answer:

Given: a projectile of initial launch velocity(V) and launch angle ∅ and no air resistance. At the maximum height, the projectile would have a zero contribution of speed from the vertical component(Vy) Therefore, if we say Vx=Vcos∅ is the only speed the projectile has at the instant of maximum height then we can replace Vx with 1/5V and write 1/5V=Vcos∅. Solving for the the launch angle ∅, gives Inverse Cos(1/5)=78.5 degrees.

6 0
3 years ago
Calculate the number of free electrons per cubic meter for some hypothetical metal, assuming that there are 1.3 free electrons p
boyakko [2]

Answer:

The number of free electrons per cubic meter is 7.61\times 10^{28}\ m^{-3}

Explanation:

It is given that,

The number of free electrons per cubic meter is, 1.3

Electrical conductivity of metal, \sigma=6.8\times 10^7\ \Omega^{-1}m^{-1}

Density of metal, \rho=10.5\ g/cm^3

Atomic weight, A = 107.87 g/mol

Let n is the number of  free electrons per cubic meter such that,

n=1.3\ N

n=1.3(\dfrac{\rho N_A}{A})

Where

\rho is the density of silver atom

N_A is the Avogadro number

A is the atomic weight of silver

n=1.3\times (\dfrac{10.5\ g/cm^3\times 6.02\times 10^{23}\ atoms/mol}{107.87\ g/mol})

n=7.61\times 10^{22}\ cm^{-3}

or

n=7.61\times 10^{28}\ m^{-3}

Hence, this is the required solution.

6 0
3 years ago
Two blocks of masses m1 and m2 are connected to each other on an Atwood machine (the blocks are connected by a string going over
ddd [48]

Answer:211.11 gm

Explanation:

Given

mass of lighter block m_1=100 gm

mass of heavier  block is m_2

acceleration of system a=3.5 m/s^2

From diagram

for lighter block

T-m_1g=m_1a

T=m_1(g+a)

For heavier Block

m_2g-T=m_2a

T=m_2(g-a)

Equating Tension T

m_1(g+a)=m_2(g-a)

m_2=m_1\cdot \frac{g+a}{g-a}

m_2=m_1\cdot \frac{9.8+3.5}{9.8-3.5}

m_2=0.1\cdot 2.11

m_2=0.2111 kg

m_2=211.11 gm

8 0
3 years ago
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