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3 years ago

If the mass of a ball is 20 kg and it accelerates 5 m/s2, find the Force applied to it. F=_N

Physics

2 answers:

wariber [46]3 years ago

7 0

Answer: f= 100n

Explanation: So you will have to multiply 20kg to 5m/s2 and that how you will get F= 100N

lutik1710 [3]3 years ago

4 0

It will be 100N :)
20kgx5m/s^2=100N

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ou are walking down a straight path in a park and notice there is another person walking some distance ahead of you. The distanc

alexgriva [62]

Answer:

The value is $d = 31.45 \ m$

Explanation:

Generally the relative speed at which you are moving with respect to the person ahead of you is mathematically represented as

$v_r = v_s - v_c$

substituting 1.05 m/s for $v_c$ and 2.75 m/s for $v_s$

$v_r = 2.75 - 1.05$

=> $v_r = 1.7 \ m/s$

Generally the distance by which the person is ahead of you is mathematically represented as

$d = v_r * t$

substituting 18.5 s for $t$

$d = 1.7 * 18.5$

=> $d = 31.45 \ m$

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3 years ago

The weight of an astronaut on the moon is the same as on Earth.<br> True<br> False

Vaselesa [24]

Answer:

False

Explanation:

This is due to the gravitational pull, since the moon does not have the same force or gravity like Earth, your weight would change.

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5 0

3 years ago

Read 2 more answers

Which combination of elements will form an ionic bond?

Anna007 [38]

Answer:

Explanation:

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3 years ago

John throws a ball with a velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?

umka21 [38]

The horizontal component of the velocity is equal to: D. 15 m/s.

<u>Given the following data:</u>

Velocity = 30 m/s

Angle = 60°

To determine the horizontal component of the velocity:

The horizontal component of the velocity represents the influence of velocity in displacing an object or projectile in the horizontal direction.

Mathematically, the horizontal component of velocity is given by the formula:

$V_x = Vcos(\theta)$

Substituting the given parameters into the formula, we have;

$\\\\V_x = 30cos(60)\\\\V_x = 30 \times 0.5$

Horizontal component, Vx = 15 m/s

Read more on horizontal component here: brainly.com/question/24681896

6 0

3 years ago

A rotating object has an angular acceleration of α = 0 rad/s2. Which one or more of the following three statements is consistent

Murrr4er [49]

Answer:

A,B and C

Explanation:

Statement A

At all times, angular velocity is $\omega = 0\,{\rm{rad/s}$

Angular acceleration is the rate of change in angular velocity with respect to time.

Angular velocity and angular acceleration are related by

${\omega _{\rm{f}}} = {\omega _{\rm{i}}} + \alpha t$

Which when re-arranged becomes

$\alpha = \frac{{{\omega _{\rm{f}}} - {\omega _{\rm{i}}}}}{t}$

There’s no change in angular velocity anytime when the angular velocity is $\omega = 0\,{\rm{rad/s}}$

The equation can be modified as follows:

$\begin{array}{c}\\\alpha = \frac{{0\,{\rm{rad/s}} - 0\,{\rm{rad/s}}}}{t}\\\\ = 0\\\end{array}$

Therefore, the angular acceleration becomes zero hence statement A is valid.

Statement B

Angular acceleration is the rate of change in angular velocity with respect to time.

Angular velocity and angular acceleration are related by

${\omega _{\rm{f}}} = {\omega _{\rm{i}}} + \alpha t$

Which when re-arranged becomes

$\alpha = \frac{{{\omega _{\rm{f}}} - {\omega _{\rm{i}}}}}{t}$

There’s no change in angular velocity anytime when the angular velocity is $\omega = 10\,{\rm{rad/s}}$ .The final and initial velocities remain the same.

The equation can be modified as follows:

$\begin{array}{c}\\\alpha = \frac{{10\,{\rm{rad/s}} - 10\,{\rm{rad/s}}}}{t}\\\\ = 0\\\end{array}$

Therefore, the angular acceleration becomes zero and statement B is valid

Statement C

Angular velocity is defined as the change in the angular position with respect to time.

Angular velocity and angular displacement are related by

$\theta = \omega t$

Which can also be modified as:

${\theta _{\rm{f}}} - {\theta _{\rm{i}}}$

Note that the final position is ${\theta _{\rm{f}}}$ and initial position is ${\theta _{\rm{i}}}$

Modifying the equation to find the angular velocity we obtain

$\omega = \frac{{{\theta _{\rm{f}}} - {\theta _{\rm{i}}}}}{t}$

When the angular displacement has the same value at all times, the equation becomes

$\begin{array}{c}\\\omega = \frac{{{\theta _{\rm{i}}} - {\theta _{\rm{i}}}}}{t}\\\\ = 0\\\end{array}$

The angular velocity becomes zero.

Angular acceleration and angular velocity are related by

${\omega _{\rm{f}}} = {\omega _{\rm{i}}} + \alpha t$

The expression above can be rearranged as follows:

$\alpha = \frac{{{\omega _{\rm{f}}} - {\omega _{\rm{i}}}}}{t}$

At all times, the angular velocity is $\omega = 0\,{\rm{rad/s}}$ hence initial and final velocities remain the same

We obtain

$\begin{array}{c}\\\alpha = \frac{{0\,{\rm{rad/s}} - 0\,{\rm{rad/s}}}}{t}\\\\ = 0\\\end{array}$

Therefore, the angular acceleration becomes zero and statement C is valid.

Therefore, statements A,B and C are consistent .

4 0

4 years ago