Answer:
133.62 kmh.
Explanation:
Time provided = 3.25 hours.
Distance to be covered 300 km
Times spent in first 100 km = 1 hour
Time spent in next 43 km
= 43 / 40 = 1.075 hours
Total time spent = 2.075 hours
Total distance covered = 143 km
Distance remaining = 300 - 143
=157 km .
Time remaining = 3.25 - 2.075
= 1.175
Speed required = Distance remaining / time remaining
= 157 / 1.175
= 133.62 kmh.
Answer:
The answer is 24cm
Explanation:
This problem bothers on the curved mirrors, a concave type
Given data
Object height h= 5cm
Object distance = 12cm
Focal length f=24cm
Let the image distance be v=?
Applying the formula we have
1/v +1/u= 1/f
Substituting our given data
1/v+1/12=1/24
1/v=1/24-1/12
1/v=1-2/24
1/v=-1/24
v= - 24cm
This implies that the image is on the same side as the object and it is real
Answer:
c = 1 / √(ε₀*μ₀)
Explanation:
The speed of the electromagnetic wave in free space is given in terms of the permeability and the permittivity of free space by
c = 1 / √(ε₀*μ₀)
where the permeability of free space (μ₀) is a physical constant used often in electromagnetism and ε₀ is the permittivity of free space (a physical constant).
Answer:
No. Touching a live electric current is never a good idea.
Explanation:
Answer:
The carrier lengthen is 0.08436 m.
Explanation:
Given that,
Length = 370 m
Initial temperature = 2.0°C
Final temperature = 21°C
We need to calculate the change temperature
Using formula of change of temperature
We need to calculate the carrier lengthen
Using formula of length
Put the value into the formula
Hence, The carrier lengthen is 0.08436 m.
