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3 years ago

How many moles of H atoms are in 15.2 grams of pure ice?

Chemistry

1 answer:

nikitadnepr [17]3 years ago

6 0

The number of moles of H atoms in 15.2 grams of pure ice is 0.850 moles

The number of moles of O atoms in 15.2 grams of pure ice is 13.50 moles

An atom is a smallest indivisible particle of a chemical element that is capable of independent existence.

Pure ice contains the H2O molecules and the molar mass of H2O is 18.02 g/mol

Using the relation:

number of moles = mass/molar mass

The number of moles of H2O = 15.2 grams/18.02 g/mol

number of moles of H2O = 0.8435 moles

If the atomic mass of H and O are as follow:

the atomic mass of H atom is = 1.00784 g/mol
the atomic mass of O atom is = 15.999 g/mol

Then:

the number of H atoms in 15.2 grams of pure ice = mass of H atom × molar mass of H2O.

the number of H atoms = 0.8435 mol × 1.00784 g/mol

the number of H atoms = 0.850 moles

the number of O atoms in 15.2 grams of pure ice = 0.8435 mol × 15.999 g/mol

the number of O atoms = 13.50 moles

Learn more about atoms here:

brainly.com/question/25832904

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AleksAgata [21]

Answer:

2.25 g

Explanation:

The mass of the solid X must be the total mass (beaker + solid X) less than the mass of the beaker. Then:

mass of the solid X = 34.40 - 32.15

mass of the solid X = 2.25 g

The difference of 0.25 g must occur for several problems: an incorrect weight in the balance, the configuration of the balance, the solid can be hydrophilic and absorbs water, and others.

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3 years ago

Hydrogen sulfide burns form sulfur dioxide:

Helga [31]

Answer: 404.04 kJ.

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

moles of $H_2S$

$\text{Number of moles}=\frac{26.7g}{34.1g/mol}=0.78moles$

$2H_2S(g)+3O_2(g)\rightarrow 2SO_2(g)+2H_2O(g)$ $\Delta H=-1036kJ$

According to stoichiometry :

2 moles of $H_2S$ on burning produces = 1036 kJ

Thus 0.78 moles of $H_2S$ on burning produces = $\frac{1036kJ}{2}\times 0.78=404.04$

Thus the enthalpy change when burning 26.7 g of hydrogen sulfide is 404.04 kJ.

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3 years ago

Treatment of butanedioic (succinic) anhydride with ammonia at elevated temperature leads to a compound of molecular formula C4H5

artcher [175]

Answer:

The product is Methyl cyanoacetate

Explanation: see structure attached

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3 years ago

What does an atom become if it gains or loses electrons?

Tju [1.3M]

I think a is the answerr

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3 years ago

Complete and balance the following acid-base equations:

Alchen [17]

Answer:

a) $HClO_4 (aq) + LiOH \rightarrow LiClO_4 + H_2O$

b) $H_2SO_4(aq) + 2NaOH(aq) \rightarrow Na_2SO_4 (aq) + 2H_2O (l)$

c) $Ba(OH)2 + 2HF\rightarrow BaF_2 + 2H_2O$

Explanation:

when $HClO_4$ is added to LiOH, lithium chlorate and water is formed.

$HClO_4 (aq) + LiOH \rightarrow LiClO_4 + H_2O$

Balancing of above reaction,

It can be seen that all the atoms in both the sides are balanced. so it is a balanced reaction.

(b) When aqueous $H_2SO_4$ is added to NaOH, $Na_2SO_4$ and $H_2O$ is formed. It is a neutrilization reaction.

$H_2SO_4(aq) + NaOH(aq) \rightarrow Na_2SO_4 (aq) + H_2O (l)$

Balancing of above reaction,

First balance all the atoms except O and H

S atom is already balanced in either side

No. of Na atom in left hand side = 1

No. of Na atom in right hand side = 2

So multiply NaOH by 2, now the reaction becomes:

$H_2SO_4(aq) + 2NaOH(aq) \rightarrow Na_2SO_4 (aq) + H_2O (l)$

No. of O atoms in left hand side = 6

No. of O atoms in right hand side = 5

So multiply H2O by 2, now the reaction becomes:

$H_2SO_4(aq) + 2NaOH(aq) \rightarrow Na_2SO_4 (aq) + 2H_2O (l)$

Now, it can been seen that all the atoms are balanced.

c) When $Ba(OH)2$ reacts with HF, baroum fluoride and water is formed.

$Ba(OH)2 + HF\rightarrow BaF_2 + H_2O$

Balancing of above reaction,

Barium atoms are already balanced on either side.

No. of F atoms on left hand side = 1

No. of F atoms on right hand side = 2

So, multiply HF by 2, now reaction becomes

$Ba(OH)2 + 2HF\rightarrow BaF_2 + H_2O$

In order to balance H and O on either side, multiply H2O by 2.

$Ba(OH)2 + 2HF\rightarrow BaF_2 + 2H_2O$

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3 years ago