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dalvyx [7]
2 years ago
11

How many moles of H atoms are in 15.2 grams of pure ice?

Chemistry
1 answer:
nikitadnepr [17]2 years ago
6 0

The number of moles of H atoms in 15.2 grams of pure ice is 0.850 moles

The number of moles of O atoms in 15.2 grams of pure ice is 13.50 moles

<h3>What is an atom?</h3>

An atom is a smallest indivisible particle of a chemical element that is capable of independent existence.

  • Pure ice contains the H2O molecules and the molar mass of H2O is 18.02 g/mol

Using the relation:

  • number of moles = mass/molar mass

The number of moles of H2O = 15.2 grams/18.02 g/mol

number of moles of H2O = 0.8435 moles

If the atomic mass of H and O are as follow:

  • the atomic mass of H atom is = 1.00784 g/mol
  • the atomic mass of O atom is = 15.999 g/mol

Then:

the number of H atoms in 15.2 grams of pure ice = mass of H atom × molar mass of H2O.

the number of H atoms = 0.8435 mol × 1.00784 g/mol

the number of H atoms = 0.850 moles

the number of O atoms in 15.2 grams of pure ice = 0.8435 mol × 15.999 g/mol

the number of O atoms = 13.50 moles

Learn more about atoms here:

brainly.com/question/25832904

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Explanation:

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3 0
2 years ago
A 6.165 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 10.27 grams of CO2 and 3
e-lub [12.9K]

Answer:

Explanation:

mass of carbon in 10.27 g of CO₂ = 12 x 10.27 / 44 = 2.80 g

mass of hydrogen ( H ) in 3.363 g of H₂O = 2  x 3.363 / 18

= .373 g

These masses would have come from the sample of 6.165 g .

Rest of 6.165 g of sample is oxygen .

So oxygen in the sample = 6.165 - ( 2.8 + .373 ) = 2.992 g

Ratio of C  , H , O in the sample

2.8 : .373 : 2.992

C: H : O : : 2.8 : .373 : 2.992

Ratio of moles

C: H : O : : 2.8/12 : .373/1 : 2.992 / 16

C: H : O : : .2333 : .373 : .187

C: H : O : : .2333/.187 : .373/.187 : .187/.187

C: H : O : : 1.247 : 1.99 : 1

C: H : O : : 5 : 8 : 4 ( after multiplying by 4 )

Hence empirical formula

C₅H₈O₄

Molecular formula ( C₅H₈O₄ )n

n ( 5 x 12 + 8 x 1 + 4 x 16 ) = 132

n x ( 60 + 8 + 64 ) = 132

n = 1

Molecular formula = C₅H₈O₄.

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2 years ago
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6 0
3 years ago
How many kilojoules of heat will be released when exactly 1 mole of iron, Fe, is burned to form Fe2O3 at standard state condaiti
Diano4ka-milaya [45]

Answer:

412.1kJ

Explanation:

For the reaction , from the question -

4Fe (s)  +  3O₂ (g)  → 2Fe₂O₃ (s)

Δ Hrxn = Δ H°f (products) - Δ H°f (reactants)

In case the compound is in its standard state , enthalphy of formation is zero

Hence ,

for the above reaction ,

ΔHrxn =( 2 * Δ H° (Fe₂O₃ )) - [ ( 4 *Δ H° Fe ) + (3 * Δ H° O₂ )]

The value for Δ H°(Fe₂O₃ ) = - 824.2kJ/mol

Δ H° Fe = 0

Δ H° O₂ = 0

Putting in the above equation ,

ΔH rxn = ( 2 * Δ H° (Fe₂O₃ ))  - 0

ΔHrxn =  2× - 824.2 kJ / mol = - 1648.4 kJ/mol

- 1648.4 kJ/mol  , this much heat is released by the buring of 4 mol of Fe.

Hence ,

for 1 mol of Fe ,

- 1648.4 kJ/mol  / 4 = 412.1kJ

8 0
3 years ago
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