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dalvyx [7]
2 years ago
11

How many moles of H atoms are in 15.2 grams of pure ice?

Chemistry
1 answer:
nikitadnepr [17]2 years ago
6 0

The number of moles of H atoms in 15.2 grams of pure ice is 0.850 moles

The number of moles of O atoms in 15.2 grams of pure ice is 13.50 moles

<h3>What is an atom?</h3>

An atom is a smallest indivisible particle of a chemical element that is capable of independent existence.

  • Pure ice contains the H2O molecules and the molar mass of H2O is 18.02 g/mol

Using the relation:

  • number of moles = mass/molar mass

The number of moles of H2O = 15.2 grams/18.02 g/mol

number of moles of H2O = 0.8435 moles

If the atomic mass of H and O are as follow:

  • the atomic mass of H atom is = 1.00784 g/mol
  • the atomic mass of O atom is = 15.999 g/mol

Then:

the number of H atoms in 15.2 grams of pure ice = mass of H atom × molar mass of H2O.

the number of H atoms = 0.8435 mol × 1.00784 g/mol

the number of H atoms = 0.850 moles

the number of O atoms in 15.2 grams of pure ice = 0.8435 mol × 15.999 g/mol

the number of O atoms = 13.50 moles

Learn more about atoms here:

brainly.com/question/25832904

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Answer:

See explanation

Explanation:

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b) The boiling points of the halogen halides are much higher than that of the noble gases because the halogen halides have much higher molecular masses and stronger intermolecular forces between molecules compared to the noble gases.

Also, the change in boiling point of the hydrogen halides is much more marked(decreases rapidly)  due to decrease in the magnitude of hydrogen bonding from HF to HI. The boiling point of the noble gases increases rapidly down the group as the molecular mass of the gases increases.

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What is the molarity of a solution containing 55.8 g of mgcl2 dissolved in 1.00 l of solution?
MakcuM [25]
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Our solution contains 55.8g in 1 l  of solution, which is 55.8 g/l

Now, we need to make a proportion:
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What needs to happen for the equation CH4 + O2 → CO2 + H2O to be balanced?
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B. This is because the Hydrogen and Oxygen need balanced out.

Current-

C-1            |        C-1
H-4            |         H-2
O-2            |         O-3


Adding a coefficient of 2 before oxygen in the reactants and H2O in the products would balance this equation

<span>CH4 + 2O2 → CO2 + 2H2O</span>
C-1            |        C-1
H-4            |         H-4
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Answer:

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