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pashok25 [27]
2 years ago
8

The ratio of the specific heat of aluminum to the specific heat of iron is 2:1. How much energy must be transferred to the alumi

num pan compared with the amount of
energy transferred to the iron pan?
Chemistry
1 answer:
erastova [34]2 years ago
3 0

Given what we know about ratios, we can confirm that in comparison to the iron pan, the aluminum pan will receive twice as much heat.

<h3>Why would the aluminum pan receive double the heat?</h3>
  • This has to do with the ratio being presented.
  • A ratio of 2:1 means that for every unit of heat to the iron, the aluminum receives 2.
  • In other words, the aluminum pan receives twice as much heat when compared to the iron pan.

Therefore, we can confirm that because the ratio of heat to the aluminum in comparison to the iron pan is 2:1, this means that for every 1 unit of heat to the iron pan, the aluminum pan will receive 2. This results in double the total heat received by the aluminum pan.

To learn more about ratios visit:

brainly.com/question/1504221?referrer=searchResults

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7.6 The diagrams show the atoms in four different substances. Each circle represents an atom.
Illusion [34]

Answer:

A and C represent elements while B and D represent Compounds

Explanation:

chemical elements cannot be broken down into simpler substances by any chemical reaction. While A chemical compound is a chemical substance composed of many identical molecules composed of atoms from more than one element held together by chemical bonds

8 0
1 year ago
How many grams of carbonic acid were produced by the 3.00 g sample of NaHCO
stellarik [79]
I think the given is 3 g sample of NaHCO3. then if it will be reacted with an acid, it will produce H2CO3.
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7 0
3 years ago
f the Ksp for HgBr2 is 2.8×10−14, and the mercury ion concentration in solution is 0.085 M, what does the bromide concentration
goldfiish [28.3K]

Answer:

0.057 M

Explanation:

Step 1: Given data

Solubility product constant (Ksp) for HgBr₂: 2.8 × 10⁻⁴

Concentration of mercury (II) ion: 0.085 M

Step 2: Write the reaction for the solution of HgBr₂

HgBr₂(s) ⇄ Hg²⁺(aq) + 2 Br⁻

Step 3: Calculate the bromide concentration needed for a precipitate to occur

The Ksp is:

Ksp = 2.8 × 10⁻⁴ = [Hg²⁺] × [Br⁻]²

[Br⁻] = √(2.8 × 10⁻⁴/0.085) = 0.057 M

7 0
3 years ago
QUESTION 5<br> Match the symbol with the type of symbiotic relationship it represents
marshall27 [118]

Answer:

A : 1

B : 3

C : 4

D : 2

6 0
3 years ago
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<span>The superscripts in an electron configuration represents the number of electrons and protons in an element. </span>
8 0
3 years ago
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