Answer:
Hexose category and ketohexose category
Explanation:
The classification of the Carbohydrate tagatose by carbonyl group is that it is a monosaccharide and has a hexose structure hence it belongs to the Hexose category
Based on the number of carbon atoms the structure has a ketofunctionality hence it is classified under the ketohexose category
Attached below is the remaining part of the solution
The question is incomplete. Complete question is attached below.
..........................................................................................................................
Correct Answer: <em>Option 1) 2-pentene</em>
Reason:
Following are the IUPAC rules for naming the compound
1) Select the
longest carbon chain. In present case longest carbon chain has 5 carbon atom. Hence, it is a pentane derivative.
2) In case of alkene,
replace 'e' of alkane by 'ene'3) Give
lowest number to function group. In present case, it is double bond.
Applying above rules, the IUPAC name of compound is
2-pentene
Answer:
A
Explanation:
it has an arrow symbolizing direction because a vector quantity has both magnitude and direction.
Answer:
A.
Explanation:
The 2 - butene is an alkene with the formula C4H8, which can be used as the polybutene monomer or co-polymer. It is a compressed liquefied gas colorless, highly flammable characteristic odor. Prolonged exposure to this gas can cause frostbite causing a lowering of consciousness. Its formula is C4H8 and it is made up of 4 carbon atoms.
The best structure that describes 2-butene is that of Option A.
Answer:
See below
Step-by-step explanation:
You won't see much happening. The solution is saturated, so the salt will fall to the bottom of the container and sit there. It will not dissolve.
However, at the atomic level, Na⁺ and Cl⁻ ions are being pulled from the surface of the crystals and going into solution as hydrated ions. At other places, Na⁺ and Cl⁻ ions are returning to the surface of the crystals.
The process is
NaCl(s) ⇌ Na⁺(aq) + Cl⁻(aq)
The rates of the forward and reverse processes are equal, so you see no net change.