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Mnenie [13.5K]
3 years ago
6

Which metalloid is often found in microchips, semiconductors, and sand?a. boron b. arsenic c. germanium d. silicon​

Chemistry
2 answers:
elena-14-01-66 [18.8K]3 years ago
5 0

Answer:

silicon

Explanation:

Silicon. Silicon is often found in electronic devices, as well as the sand.

hope this helps UwU

aleksandr82 [10.1K]3 years ago
4 0

Answer:

silicon

Explanation:

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Read the text
Citrus2011 [14]

Answer:

1. EXPOSE TWO GROUPS TO THE AROMA OF CHOCOLATE CHIP COOKIES BAKING

2.HAVE ONE GROUP EAT ONLY CHOCOLATE CHIPS COOKIES, AND HAVE THE OTHER GROUP EAT ONLY RADISHES

3.

3 0
3 years ago
Which of the following observations about pH is consistent for an acidic solution?
kow [346]

Answer:

A pH value of 3

Explanation:

The pH scale has 14 numbers:

- 7 is a true natural

-anything above 7 is a base

-and anything under 7 is an acid

pH of three is a strong acid

5 0
1 year ago
What is the molar mass of HCl??
irakobra [83]
HCl = 1 + 35.5 => 36.5 g/mol

hope this helps!
7 0
4 years ago
How many moles are in 17 grams of magnesium chloride (MgCl2) ?
seraphim [82]

Answer:

Molar mass = (24.31 + 2 × 35.45) = 95.21 g mol–1 i.e. 95.21 g of MgCl2 is exactly 1 mole.

Explanation:

7 0
3 years ago
In this experiment we will be using a 0.05 M solution of HCl to determine the concentration of hydroxide (OH-) in a saturated so
gulaghasi [49]

<u>Answer:</u> The moles of hydroxide ions present in the sample is 0.0008 moles

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl.

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

We are given:

n_1=1\\M_1=0.05M\\V_1=16mL\\n_2=2\\M_2=?M\\V_2=36.0mL

Putting values in above equation, we get:

1\times 0.05\times 16=2\times M_2\times 36\\\\M_2=\frac{1\times 0.05\times 16}{2\times 36}=0.011M

To calculate the moles of hydroxide ions, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

Molarity of solution = 0.011 M

Volume of solution = 36.0 mL

Putting values in above equation, we get:

0.011=\frac{\text{Moles of }Ca(OH)_2\times 1000}{36}\\\\\text{Moles of }Ca(OH)_2=\frac{0.011\times 36}{1000}=0.0004mol

1 mole of calcium hydroxide produces 1 mole of calcium ions and 2 moles of hydroxide ions.

Moles of hydroxide ions = (0.0004 × 2) = 0.0008 moles

Hence, the moles of hydroxide ions present in the sample is 0.0008 moles

8 0
3 years ago
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