Answer:
NH4NO3 (s) --> NH4+ (aq) + NO3- (aq) H = +25.7 kJ/mol
Explanation:
Step 1: Data given
2NaHCO3(s) → Na2CO3 (s) + H2O (g) + CO2 (g) ΔH = –129 kJ
C6H6(s) → C6H6(l) ΔH=+9.87 kJ
NH4NO3(s )→ NH4+(aq) + NO3–(aq) ΔH=+25.7 kJ/mol
2C8H18(l) + 25O2(g) → 16CO2(g) + 18H2O(l) ΔH =–5,471 kJ/mol
Step 2:
2NaHCO3(s) → Na2CO3 (s) + H2O (g) + CO2 (g) H = -129 kJ:
This is the decomposition reaction of NaHCO3.
NaHCO3 will break down and form Na2CO3, H2O and CO2
⇒ the heat here is heat of decomposition
C6H6 (s) --> C6H6 (l), H = +9.87 kJ
In this reaction we'll not form a new product. Benzene will change phase. From its solid form to liquid benzene.
⇒ the heat here is heat of fusion
NH4NO3 (s) --> NH4+ (aq) + NO3- (aq) H = +25.7 kJ/mol
When solid NH4NO3 is dossolved in water. it will dissociate in ammonium ion (NH4+) and nitrate ion (NO3-).
This reaction shows a solid dissolving in water and therefore the H represents the heat of solution.
⇒ The heat here is <u>heat of solution</u>
2C8H18 (l) + 25O2 (g) --> 16CO2 (g) + 18H2O (l), H = -5,471 kJ/mol: this is a combustion reaction
This is the combustion reaction of octane. CO2 and H2O will be produced.
⇒ The heat here is heat of combustion.
