Molar mass CH4 = 16.0 g/mol

* number of moles:

932.3 / 16 => 58.26875 moles

T = 136.2 K

V = 0.560 L

P = ?

R = 0.082

Use the clapeyron equation:

P x V = n x R x T

P x 0.560 = 58.26875 x 0.082 x 136.2

P x 0.560 = 650.76

P = 650.76 / 0.560

P = 1162.07 atm

5 0

4 years ago

The dosage for an antibiotic is prescribed at 8.0 mg per kilogram of body weight taken it twice daily for 2 weeks what total mas

krek1111 [17]

Answer:

18.2784 g

Explanation:

First we convert 180 lb to kg:

1 lb = 0.453 kg

180 lb * 0.453 kg / lb = 81.6 kg

Now we calculate the mass of antibiotic taken in one day:

8.0 mg/kg * 81.6 kg = 652.8 mg

Given that it is taken twice daily, in one day the person would take (652.8 * 2) 1305.6 mg. In grams that mass would be:

1305.6 mg / 1000 = 1.3056 g

Finally we multiply those 1.3056 daily grams by the 14 days in two weeks:

(1.3056 g) * 14 = 18.2784 g

7 0

3 years ago

Please help me thank u !

konstantin123 [22]

You should just try your best out what u think it will be okay ! I don’t know the answer I’m sorry

8 0

3 years ago

__C8H18(I) + __ O2(g) —> __Co2(g) + __H2O(g) Balance out the equation

C8H18(I) + O2(g) —> Co2(g) + H2O(g) Balance out the equation