Answer:
![\left[\begin{array}{cccc}1&0&1&|-1\\-3&-9&3&|27\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C-3%26-9%263%26%7C27%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given [Missing from the question]
![\left[\begin{array}{cccc}1&0&1&|-1\\1&3&-1&|-9\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C1%263%26-1%26%7C-9%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
Required
This implies that, we form a new matrix where the second row of the new matrix is a product of -3 and the second row of the previous matrix.
So, we have:
![Initial =\left[\begin{array}{cccc}1&0&1&|-1\\1&3&-1&|-9\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=Initial%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C1%263%26-1%26%7C-9%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
![New =\left[\begin{array}{cccc}1&0&1&|-1\\-3*1&-3*3&-3*-1&|-3*-9\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=New%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C-3%2A1%26-3%2A3%26-3%2A-1%26%7C-3%2A-9%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
![New =\left[\begin{array}{cccc}1&0&1&|-1\\-3&-9&3&|27\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=New%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C-3%26-9%263%26%7C27%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
First you want to make an equation to express the problem. For this one in particular, let's make the length be represented by "L" and the width "W."
The length minus three times the width is 1 foot. This can be represented as L - 3W = 1. This means that L = 3W + 1. This will be our substitute for the length.
The perimeter of a rectangle is 2 times the length plus the width P = 2(L + W). By substituting these variables from what we now know we can find out the dimensions of the rectangle.
42 = 2(3W + 1 + W)
42 = 6W + 2 + 2W Multiply <u>everything in parenthesis</u> by 2.
42 = 8W + 2 Add the like terms.
40 = 8W Subtract 2 on both sides to get the <em>variable (W) </em>by itself.
5 = W Divide 8 from 40 to get what W equals.
The width is equal to 5. We can now plug in this answer to the original equation (P = 2(L + W)) or the length equation we made earlier (L = 3W + 1) to find the length.
42 = 2(L + 5)
42 = 2L + 10 Multiply <u>everything in parenthesis<em /></u><u><em /></u> by 2.<u />
32 = 2L Subtract 10 from both sides to get the <em>variable (L) </em>by itself.
16 = L Divide 2 from 32 to get what L equals.
<u>Or</u><u />
L = 3(5) + 1 Replace the <em>variable (W) </em>with 5.
L = 15 + 1 Multiply 3 by 5 to get 15.
L = 16 Add the remaining terms!
So the dimensions of the rectangle are 5 and 16, where 5 is the width and 16 is the length. I hope this answer made sense and that you can solve these on your own in the future!
Answer:
Step-by-step explanation:
AC = 50 cm
BC = 14 cm
Pythagorean theorem,
AB² + BC² = AC²
AB² + 14² = 50²
AB² + 196 = 2500
AB² = 2500 - 196
AB² = 2304
AB = √2304
AB = 48 cm
Answer:
(2*100,000)+(7*10,000)+(9*100)+(5*10)
Answer:
y=√x+5 -1
the answer is option C,,
x=-7,y=√-7+5 -1=√-2 -1
we can't find the square root of negative values, therefore it displays as error
x=-6,y=√-6+5-1=√-1 -1
same reason
x=-5,y=√-5+5-1=√0-1=-1
x=-4,y=√-4+5-1=√1-1=0
x=-1,y=√-1+5-1=√4-1=1
x=4,y=√4+5-1=√9-1=2
