Answer:
The acceleration of a 1000 kg car subject to a 550 N net force = 0.55 m/s^2
Explanation:
Given:
F = 550 N
m = 1000 kg
To Find:
a = ?
Solution:
So by the equation by Newton's 2nd Law of Motion,
F = m x a
550 N = 1000 kg x a
a = 550 N/ 1000 kg
a = 0.55 m/s^2
Therefore,
The acceleration of a 1000 kg car subject to a 550 N net force = 0.55 m/s^2
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Answer:
First, let’s correct the question. Acceleration is the rate of change in velocity. Its unit therefore is ft/sec/sec. If S is the distance traveled for a given duration, S = Vot + (1/2)at^2 where Vo is the initial velocity, a is the acceleration and t is the time. For Vo = 0, a = 6m/sec/sec and t = 3 sec. The distance traveled is S = 0 + (1/2) x 6 x 3^2 = 27 meters
The absorption spectrum would have all the wavelengths of the light source but would have black lines where the two red and one orange lines were in the emission spectrum
Option B would be right one
according to momentum conservation
6600*2 = 13200kgm/s
5400*3 = 16200kgm/s
16200-13200 = 3000
now 6600-5400 = 1200 kg
thus 3000/1200 = 2.5 v
<span>The periodic table is the most important chemistry reference there is. It arranges all the known elements in an informative array. Elements are arranged left to right and top to bottom in order of increasing atomic number. Order generally coincides with increasing atomic mass.
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