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Mashutka [201]
3 years ago
10

Pre-Test

Physics
1 answer:
SSSSS [86.1K]3 years ago
4 0

Answer:

the atom cannot be divided into smaller particles

electrons orbit around the center of the atom

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Ocean waves are hitting a beach with a frequency of 0.100 Hz. Their average wavelength is 15.0 m. What is their average speed?
den301095 [7]

Answer:

Average speed=1.5 m/s

Frequency of pendulum=93.75Hz

Explanation:

We are given

Frequency, f=0.100Hz

Average wavelength =\lambda=15m

Speed of pendulum, v=30m/s

Wavelength, \lambda'=0.32m

We have to find the average speed and frequency of pendulum.

We know that

Speed,v=\lambda f

Using the formula

Average speed,v=15\times 0.1=1.5m/s

Hence, the average speed =1.5m/s

Frequency, f=\frac{v}{\lambda'}

Using the formula

f=\frac{30}{0.32}

f=93.75Hz

Hence, the frequency of a pendulum=93.75Hz

6 0
2 years ago
PLEASE HELP ASAP
morpeh [17]
A is the correct answer
7 0
3 years ago
Write a short summary paragraph that could go at the end of the text
UNO [17]

Answer:

The electro magnesium of the atoms cause the magnetic force to charge thus creating electricity. just kidding

Explanation:

If you read on the second paragraph it states that magnesium charged created electricity.

3 0
2 years ago
Riders in a carnival ride stand with their backs against the wall of a circular room of diameter
Veseljchak [2.6K]

Answer:

option C

Explanation:

given,

diameter of circular room = 8 m

rotational velocity of the rider = 45 rev/min

                  = 45 \times \dfrac{2\pi}{60}

                  =4.712 rad/s

here in this case normal force is equal to centripetal force

N = m r ω²

N = m x 4 x 4.712²

N = 88.83m

frictional force = μ N

    = 88.83m x μ

now, for the body to not to slide

gravity force is equal to frictional force

m g = 88.83 m x μ

g = 88.83 x μ

9.8 = 88.83 x μ

 μ = 0.11

hence, the correct answer  is option C

6 0
3 years ago
In a heat engine if 1000 j of heat enters the system the piston does 500 j of work, what is the final internal energy of the sys
nydimaria [60]

Answer : The final energy of the system if the initial energy was 2000 J is, 3500 J

Solution :

(1) The equation used is,

\Delta U=q+w\\\\U_{final}-U_{initial}=q+w

where,

U_{final} = final internal energy

U_{initial} = initial internal energy

q = heat energy

w = work done

(2) The known variables are, q, w and U_{initial}

initial internal energy = U_{initial} = 2000 J

heat energy = q = 1000 J

work done = w = 500 J

(3) Now plug the numbers into the equation, we get

U_{final}-(2000J)=(1000J)+(500J)

(4) By solving the terms, we get

U_{final}-(2000J)=(1000J)+(500J)

U_{final}-(2000J)=1500J

U_{final}=2000J+1500J

U_{final}=3500J

(5) Therefore, the final energy of the system if the initial energy was 2000 J is, 3500 J

5 0
3 years ago
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