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3 years ago

Pre-Test

Physics

1 answer:

SSSSS [86.1K]3 years ago

4 0

Answer:

the atom cannot be divided into smaller particles

electrons orbit around the center of the atom

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Ocean waves are hitting a beach with a frequency of 0.100 Hz. Their average wavelength is 15.0 m. What is their average speed?

den301095 [7]

Answer:

Average speed=1.5 m/s

Frequency of pendulum=93.75Hz

Explanation:

We are given

Frequency, $f=0.100Hz$

Average wavelength = $\lambda=15m$

Speed of pendulum, $v=30m/s$

Wavelength, $\lambda'=0.32m$

We have to find the average speed and frequency of pendulum.

We know that

Speed, $v=\lambda f$

Using the formula

Average speed, $v=15\times 0.1=1.5m/s$

Hence, the average speed =1.5m/s

Frequency, $f=\frac{v}{\lambda'}$

Using the formula

$f=\frac{30}{0.32}$

$f=93.75Hz$

Hence, the frequency of a pendulum=93.75Hz

6 0

2 years ago

PLEASE HELP ASAP

morpeh [17]

A is the correct answer

7 0

3 years ago

Write a short summary paragraph that could go at the end of the text

UNO [17]

Answer:

The electro magnesium of the atoms cause the magnetic force to charge thus creating electricity. just kidding

Explanation:

If you read on the second paragraph it states that magnesium charged created electricity.

3 0

2 years ago

Riders in a carnival ride stand with their backs against the wall of a circular room of diameter

Veseljchak [2.6K]

Answer:

option C

Explanation:

given,

diameter of circular room = 8 m

rotational velocity of the rider = 45 rev/min

= $45 \times \dfrac{2\pi}{60}$

=4.712 rad/s

here in this case normal force is equal to centripetal force

N = m r ω²

N = m x 4 x 4.712²

N = 88.83m

frictional force = μ N

= 88.83m x μ

now, for the body to not to slide

gravity force is equal to frictional force

m g = 88.83 m x μ

g = 88.83 x μ

9.8 = 88.83 x μ

μ = 0.11

hence, the correct answer is option C

6 0

3 years ago

In a heat engine if 1000 j of heat enters the system the piston does 500 j of work, what is the final internal energy of the sys

nydimaria [60]

Answer : The final energy of the system if the initial energy was 2000 J is, 3500 J

Solution :

(1) The equation used is,

$\Delta U=q+w\\\\U_{final}-U_{initial}=q+w$

where,

$U_{final}$ = final internal energy

$U_{initial}$ = initial internal energy

q = heat energy

w = work done

(2) The known variables are, q, w and $U_{initial}$

initial internal energy = $U_{initial}$ = 2000 J

heat energy = q = 1000 J

work done = w = 500 J

(3) Now plug the numbers into the equation, we get

$U_{final}-(2000J)=(1000J)+(500J)$

(4) By solving the terms, we get

$U_{final}-(2000J)=(1000J)+(500J)$

$U_{final}-(2000J)=1500J$

$U_{final}=2000J+1500J$

$U_{final}=3500J$

(5) Therefore, the final energy of the system if the initial energy was 2000 J is, 3500 J

5 0

3 years ago