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Neporo4naja [7]

2 years ago

5

A Man is pulling a trolley on a horizontal road with a force of 200N making 30° with the road . Find the horizontal and vertical

components of it's force .
Thank you.....~

2 answers:

artcher [175]2 years ago

6 0

The horizontal component of the force is 173.2 N.

The vertical component of the force is 100 N.

The given parameters:

Applied force, F = 200 N
Angle of inclination, Ф = 30⁰

<h3>Horizontal component of the force</h3>

The horizontal component of the force is calculated as follows;

$F_x = Fcos(\theta)\\\\
F_x = 200 \times cos(30)\\\\
F_x = 173.2 \ N$

<h3>Vertical component of the force</h3>

The vertical component of the force is calculated as follows;

$F_y =F sin(\theta)\\\\
F_y= 200 \times sin(30)\\\\
F_y = 100 \ N$

Learn more about components of forces here: brainly.com/question/8106035

natulia [17]2 years ago

3 0

$\huge\red{\mid{\fbox{\tt{ANSWER }}\mid}}$

Given:

$Force \: on \: the \: Trolley = 200N \: Angle \: with \: the \: road = 30°$

To Find:

Horizontal and Vertical components of force

Solution :

Horizontal component = FCos

$= 200Cos \: 30°$

$= 200 \: x \: √3/2$

$= 173.2 N$

Horizontal component of force is

$173.2 N$

Vertical component = Fsin

$= 200 \: Without \: 30 °$

$= 200×1/2$

$=100 N$

Vertical component of force is 100 N

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