Question

A Man is pulling a trolley on a horizontal road with a force of 200N making 30° with the road . Find the horizontal and vertical components of it's force .
Thank you.....~​

Answer 1

The horizontal component of the force is 173.2 N.

The vertical component of the force is 100 N.

The given parameters:

• Applied force, F = 200 N
• Angle of inclination, Ф = 30⁰

Horizontal component of the force

The horizontal component of the force is calculated as follows;

$F_x = Fcos(\theta)\\\\ F_x = 200 \times cos(30)\\\\ F_x = 173.2 \ N$

Vertical component of the force

The vertical component of the force is calculated as follows;

$F_y =F sin(\theta)\\\\ F_y= 200 \times sin(30)\\\\ F_y = 100 \ N$

Learn more about components of forces here: brainly.com/question/8106035

Answer 2

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Given:

$Force \: on \: the \: Trolley = 200N \: Angle \: with \: the \: road = 30°$

To Find:

Horizontal and Vertical components of force

Solution :

• Horizontal component = FCos

$= 200Cos \: 30°$

$= 200 \: x \: √3/2$

$= 173.2 N$

Horizontal component of force is

$173.2 N$

Vertical component = Fsin

$= 200 \: Without \: 30 °$

$= 200×1/2$

$=100 N$

Vertical component of force is 100 N