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AnnZ [28]
3 years ago
12

A hiker walked a hiking trail according to the chart below. What is a possible explanation of the hiker's movement?

Physics
1 answer:
joja [24]3 years ago
6 0
<span>a.The hiker had an easy, level trail from 11:00-12:00 and was able to travel the fastest during that time period.---> may be because this was indeed fastest  stage


b.The hiker got tired and walked the slowest from 1:00-2:00.---> no, because this was not the slowest stage


c.The hiker stopped for lunch from 11:00-12:00 and that slowed him down.---> no because this was the fastest stage


d.The hiker ended up in the same place that he started.---> no, because the hiker walked more toward east than toward west and more toward south than toward north.

Answer: option a)
</span>
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inessss [21]
I dont have a calculator but the equation for average acceleration is a=(change in velocity)/time. Subtract the intial velocity by the final and divide that by time
7 0
3 years ago
A) Using Excel, or some other graphing software, plot the values of y as a function of x. (You will not submit this spreadsheet.
tiny-mole [99]

Answer:

   y = 1.06 x + 0.14

            r² = 0.95

Explanation:

a) To make this graph, a spreadsheet-type calculation program is used, see attached.

On the y axis are the measured values

On the x-axis, the values ​​checked in the experiment are placed.

From the graph we see that a linear graph and that one of the values ​​has a strong deviation with respect to the others

b) The red line is the best straight line that can be drawn,

    for this the quality ajust is r²  

the closer to 1 the better the fit

           

the equation of the line is

            y = 1.06 x + 0.14

            r² = 0.95

3 0
3 years ago
A 26.0-kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 225 N. For the first 11.0 m th
frozen [14]

Answer:

18 m/s

Explanation:

Force is given by mass × acceleration

<em>F = ma</em>

<em>a = F/m</em>

For the first 11.0 m, there is no friction. Hence, the constant force is applied fully on the crate. The acceleration is

<em>a = </em>225/26.0<em> </em>m/s²

By the equation of motion, <em>v² = u² + 2as</em>

where <em>v</em> is the final velocity, <em>u</em> is the initial velocity, <em>a</em> is the acceleration and <em>s</em> is the distance travelled.

Using the values for the first part of the motion,

<em>v² = </em>0² + 2 × 8.65 × 11.0

<em>v = </em>13.8 m/s

This is the initial velocity for the second part of the motion. This part has friction of coefficient 0.20.

The frictional force = 0.20 × weight = 0.20 × 26.0 × 9.8 = 50.96 N

The effective force moving the crate in the second motion = 225 - 50.96 N = 174.04 N

This gives an acceleration of 174.04/26.0 = 6.69 m/s².

Using parameters for the equation of motion, <em>v² = u² + 2as</em>

<em>v² = </em>13.8² + 2 × 6.69 × 10 = 324.24

<em>v = </em>18<em> </em>m/s

8 0
4 years ago
Muatan listrik yang mengalir dari potensial tinggi ke potensial rendah disebut
igomit [66]

Answer:

Muatan listrik yang mengalir dari potensial tinggi ke potensial rendah disebut

elektron

Explanation:

semoga ini membantu (:

8 0
3 years ago
If an object is dropped from a tall building and hits the ground 3.0 s. later, what is the magnitude of the object's displacemen
marin [14]

Find the velocity of the object after one second.  

v = vo + at  

v = (0 m/s) + (9.8 m/s^2)(1 s)  

v = 9.8 m/s  

Now, using that, you can find the displacement in that one second between 1 and 2.  

d = vot + (1/2)at^2  

d = (9.8 m/s)(1 s) + (1/2)(9.8 m/s^2)(1 s)^2  

d = 14.7 m  


5 0
3 years ago
Read 2 more answers
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