Answer:
836.8J
Explanation:
Heat energy = ?
Mass = 100g
Initial temperature (T1) = 21°C
Final temperature (T2) = 23°C
Specific heat capacity of water (c) = 4.184J/g°C
To solve this question, we'll need to use the formula for calculating heat energy of a substance.
Q = mc∇t
Q = heat energy of substance
M = mass of substance
C = specific heat capacity of substance
∇t = change in temperature = T2 - T1
Q = 100 × 4.184 × (23 -21)
Q = 418.4 × 2
Q = 836.8J
The heat energy required to raise 100g of water from 21°C to 23°C is 836.8J
Hey there!:
Molar mass NaCl = 58.44 g/mol
Number of moles:
n = mass of solute / molar mass
n = 15.6 / 58.44
n = <span>0.2669 moles of NaCl
hope this helps!</span>
By applying the ideal gas law, PV=nRT
<span>If a car is traveling on the highway at a constant velocity, the force that pushes the car forward must be
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