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Step2247 [10]
3 years ago
10

Find the percent composition of OXYGEN in Manganese (III) nitrate, Mn(NO3)3.

Chemistry
1 answer:
Minchanka [31]3 years ago
6 0

Answer:

Mn(NO3)3 Molar mass = (54.93) + (3 x 14) + (9 x 16) = 240.93g/mol

Total number of Oxygen atoms in formula = 9

Total mass of oxygen atoms theoretically in the formula = 9x16 = 144g/mol

Oxygen's percentage composition:

(144/240.93) x 100 = 59.7% of the compound is oxygen

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Answer:

The Answer should be Endothermic reaction

Explanation:

Reactions in which energy is absorbed are called Endothermic reactions.

7 0
2 years ago
An object has a mass of 45.0 g and a volume of 4.0 ml. what is its density?
andreev551 [17]

Answer:

The answer is

<h2>11.25 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass = 45 g

volume = 4 mL

Substitute the values into the above formula and solve for the density

We have

Density =  \frac{45}{4}

We have the final answer as

<h3>11.25 g/mL</h3>

Hope this helps you

4 0
3 years ago
C5H6 reacts with itself to form C10H12 according to the following process
swat32
When carbon compounds react with themselves to form a larger molecule the process is called polymerization. Specifically addition polymerization. sometimes molecules containing containing carbon to carbon double bonds can join together to form longer chains. The double bond is broken and the electrons in it join to neighboring molecules. 
4 0
3 years ago
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Alecsey [184]

Answer: hope this helps:)

Explanation:

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7 0
3 years ago
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