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Step2247 [10]
3 years ago
10

Find the percent composition of OXYGEN in Manganese (III) nitrate, Mn(NO3)3.

Chemistry
1 answer:
Minchanka [31]3 years ago
6 0

Answer:

Mn(NO3)3 Molar mass = (54.93) + (3 x 14) + (9 x 16) = 240.93g/mol

Total number of Oxygen atoms in formula = 9

Total mass of oxygen atoms theoretically in the formula = 9x16 = 144g/mol

Oxygen's percentage composition:

(144/240.93) x 100 = 59.7% of the compound is oxygen

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Classify each of the observed changes according to whether or not they are likely to represent evidence that a chemical reaction
Mama L [17]

Answer:

a solution color becoming less intense  due to dilution- is not an evidence of a chemical reaction

bubbles (gas formation) - evidence of a chemical reaction

explosion or fire - evidence of a chemical reaction

changes in color- evidence of a chemical reaction

precipitation- evidence of a chemical reaction

changes in temperature - evidence of a chemical reaction

a solid liquifying - is not an evidence of a chemical reaction

solution colors mixing - is not an evidence of a chemical reaction

Explanation:

A chemical change is not easily reversible and yields new substances. It is often accompanied by a loss or gain of heat.

In the answer section, i have shown some evidences that lead us to conclude that a chemical reaction has taken place. The occurrence of a chemical change often goes with the formation of new substances as earlier stated and any of these signs may accompany the process.

For instance, when a metal is dropped in dilute acid solution, bubble of hydrogen gas indicates that a chemical reaction has taken place.

8 0
3 years ago
You run an experiment in which two substances chemically react in a closed system. you run the same experiment in an open system
m_a_m_a [10]

If we run an experiment in which two substances chemically react in a closed system and then we run the same experiment in an open system, then the masses of the products in each experiment will be different because the open system allows the interchange of matter and energy with the media.

<h3>What is an open system?</h3>

An open system is an interrelated group pf parts that work together to interchange matter and energy with the surrounding environment, while a closed system does not generate an exchange of matter and energy.

Therefore, with this data, we can see that an open system interchange energy and matter with the environment, while closes systems do it.

Learn more about open systems here:

brainly.com/question/28891854

#SPJ1

6 0
1 year ago
effect. RbClO(s) → Rb+(aq) + ClO−(aq) HClO(aq) + H2O(l) equilibrium reaction arrow H3O+(aq) + ClO−(aq) The degree of dissociatio
Lemur [1.5K]

Explanation:

Common ion effect is defined as the effect which occurs on equilibrium when a common ion (an ion which is already present in the solution) is added to a solution. This effect generally decreases the solubility of a solute.

Equilibrium reaction of strontium sulfate and sodium sulfate follows the equation:

RbClO(s)\rightarrow Rb^{+}(aq.)+ClO^{-}(aq.)

HClO(aq)+H_2O\rightleftharpoons H_3O^+(aq.)+ClO^{-}(aq.)

According to Le-Chateliers principle: If there is any change in the variables of the reaction, the equilibrium will shift in the direction in order to minimize the effect.

In the equilibrium reactions, hypochlorite ion is getting increased on the product side, so the equilibrium will shift in the direction to minimize this effect, which is in the direction of hydrogen hypochlorite.

Thus, the addition hypochlorite ions will shift the equilibrium in the left direction.

The dissociation of hydrogen hypochlorite is suppressed due to the common ion effect.

8 0
3 years ago
Question 6 (1 point)
Morgarella [4.7K]

Answer:

question 6: winter solstice

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8 0
3 years ago
The compound cisplatin has been extensively studied as an antitumor agent. It is synthesized by the following, unbalanced reacti
zimovet [89]
The balanced chemical equation would be as follows:

<span>K2PtCl4(aq) + 2NH3(aq) --> Pt(NH3)2Cl2(s) + 2KCl(aq)

We are given the amount of </span>K2PtCl4 to be used in the reaction. This will be the starting point for our calculations. We do as follows:

65 g K2PtCl4 ( 1 mol / 415.09 g ) ( 1 mol Pt(NH3)2Cl2 / 1 mol K2PtCl ) ( 300.051 g / 1 mol ) = 46.99 g Pt(NH3)2Cl produced 
6 0
3 years ago
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