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Step2247 [10]
3 years ago
10

Find the percent composition of OXYGEN in Manganese (III) nitrate, Mn(NO3)3.

Chemistry
1 answer:
Minchanka [31]3 years ago
6 0

Answer:

Mn(NO3)3 Molar mass = (54.93) + (3 x 14) + (9 x 16) = 240.93g/mol

Total number of Oxygen atoms in formula = 9

Total mass of oxygen atoms theoretically in the formula = 9x16 = 144g/mol

Oxygen's percentage composition:

(144/240.93) x 100 = 59.7% of the compound is oxygen

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Subduction zone is the answer
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Aluminum chlorate<br> +<br> barium sulfate → aluminum sulfate + barium chlorate
Virty [35]

Balanced equation

2Al(ClO₃)₃ + 3BaSO₄⇒ Al₂(SO₄)₃ + 3Ba(ClO₃)₂

<h3>Further explanation</h3>

Given

Word equation

Required

Chemical equation

Solution

Chemical equations can be expressed in

  • word equation
  • skeleton equation
  • balanced equation

Aluminum chlorate = Al(ClO₃)₃

Barium sulfate = BaSO₄

Aluminum sulfate = Al₂(SO₄)₃

Barium chlorate = Ba(ClO₃)₂

  • Skeleton equation

Al(ClO₃)₃ + BaSO₄⇒ Al₂(SO₄)₃ + Ba(ClO₃)₂

  • Balanced equation

2Al(ClO₃)₃ + 3BaSO₄⇒ Al₂(SO₄)₃ + 3Ba(ClO₃)₂

6 0
3 years ago
Which of these is an accurate source of evidence for an investigation?
Feliz [49]

Answer:

observations

Explanation:

4 0
3 years ago
A gas has a volume of 420 L at a temperature of -42.0 degrees celsius. What volume will the gas occupy at 18.0 degrees celsius?
Hoochie [10]

Formula

V/T = V1/T1

Givens

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The pressure is a constant.

Solution

420/231 = V1/291         Multiply by 291

420*291 / 231 = V1

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6 0
4 years ago
4 points<br> 9. Name the scientists that played a major role in the development of cell theory. *
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Hope this helps

Have a great day/night
5 0
3 years ago
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