Which equilibrium system has HCO3- acting as a Brønsted-Lowry base?

1 answer:

8 0

A Brønsted-Lowry base is a base is a proton acceptor.

In the only case where this is done is when HCO3- accepts a proton and becomes H2CO3.

In the other cases, HCO3- is donating a proton which makes it an acid.

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Solid aluminum and gaseous oxygen read in a combination reaction to produce aluminum oxide. 4Al(s) + 3O_2(g) rightarrow 2Al_2O_3

Kryger [21]

Answer:

4.7 g. Option 5 is the right one.

Explanation:

4Al(s) + 3O₂ (g) ⇄ 2Al₂O₃ (s)

We convert the mass of reactants to moles, in order to determine the limiting.

2.5 g Al / 26.98 g/mol → 0.092 moles of Al

2.5 g O₂ / 32g/mol → 0.078 moles of O₂

Ratio is 4:3. 4 moles of Al react with 3 moles of O₂

Then, 0.092 moles of O₂ would react with (0.092 . 3)/ 4 = 0.069 moles O₂

We have 0.078 moles of O₂ and we need 0.069 moles, the oxygen is the limiting in excess. Therefore the Al is the limiting reactant.

Ratio is 4:2. 4 moles of Al, can produce 2 moles of Al₂O₃

Then, 0.092 moles of Al would produce (0.092 .2) / 4 = 0.046 moles

If we convert the moles to mass, we find the anwer:

0.046 mol . 101.96 g/mol = 4.69 g

5 0

3 years ago

A gas occupies a volume of 180 mL at 35oC and 740 mmHg. What is the volume of the gas at STP?

Tasya [4]

Answer:

there you go

Explanation:

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3 years ago

What is the number of sub shells in the 3rd main shell?

valkas [14]

The answer would be 2

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A conjugate base is the species that

malfutka [58]

A conjugate base is the species that D. Remains after an acid has given up a single proton.

It is the deprotonated form of the acid.

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Formaldehyde has the formula ch2o. how many molecules are there in 0.11 g of formaldehyde

jeka57 [31]

Answer: 2.21 x $10^{21}$ molecule

To answer this question, you need to know the formaldehyde molecular mass.
Formaldehyde molecular weight would be 12+ 1(2) + 16= 30 g/mol
After knowing the molecular mass you can count how many molecules by multiplying it by Avogadro's number. The calculation would be:
0.11g / (30g/mol) x 6.022140857 × $10^{23}$ = 0.02208 x $10^{23}$ = 2.21 x $10^{21}$

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3 years ago