They are all pentoses. In their linear forms, they all contain carbon carboxyl and several hydroxyl functional groups. In their linear forms, they all contain a carbonyl and several hydroxyl functional groups.
Carbon is a chemical element with the symbol C and atomic number 6. Carbon is a non-metal and is tetravalent. That atom donates four electrons to form a covalent chemical bond. It belongs to group 14 of the periodic table. Carbon makes up only about 0.025% of the Earth's crust.
Carbon is used in some form in almost every industry in the world. It is used as fuel in the form of coal, methane gas, and crude oil (used to make gasoline). It is used to make all sorts of materials, including plastics and alloys such as steel (a combination of carbon and iron). Carbon is also found in fossil fuels such as petroleum (crude oil), coal and natural gas. Carbon is also found in dead, decaying animals and animal waste soils. Carbon is stored in the biosphere of plants and trees.
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The change in pressure in a sealed 10.0L vessel is 5.28 atm
<u><em>calculation</em></u>
The pressure is calculated using the ideal gas equation
That is P=n RT
where;
P (pressure)= ?
v( volume) = 10.0 L
n( number of moles) which is calculated as below
<em>write the equation for decomposition of NH₄NO₂</em>
NH₄NO₂ → N₂ +2H₂O
<em>Find the moles of NH₄NO₂</em>
moles = molarity x volume in liters
= 2.40 l x 0.900 M =2.16 moles
<em>Use the mole ratio to determine the moles of N₂</em>
that is from equation above NH₄NO₂:N₂ is 1:1 therefore the moles of N₂ is also =2.16 moles
R(gas constant) =0.0821 l.atm/mol.K
T(temperature) = 25° c into kelvin = 25 +273 =298 K
make p the subject of the formula by diving both side by V
P = nRT/V
p ={ (2.16 moles x 0.0821 L.atm/mol.K x 298 K) /10.0 L} = 5.28 atm.
Ur answer is A
hshsbdndnensj
Answer:
A. Methanol
B. 2-chloropropan-1-ol
C. 2,2-dichloroethanol
D. 2,2-difluoropropan-1-ol
Explanation:
Primary alcohols are stronger acids than secondary alcohols which are stronger than tertiary alcohols.
This trend is so because of the stability of the alkoxide ion formed(stabilising the base, increases the acidity). A more stabilised alkoxide ion is a weaker conjugate base (dissociation of an acid in water).
By electronic factors, When there are alkyl groups donating electrons, the density of electrons on th O- will increase a d thereby make it less stable.
By stearic factors, More alkyl group bonded to the -OH would mean the bulkier the alkoxide ion which would be harder to stabilise.
Down the group of the periodic table, basicity (metallic character) decreases as we go from F– to Cl– to Br– to I– because that negative charge is being spread out over a larger volume that is electronegativity decreases down the group.
Electronegative atoms give rise to inductive effect and a decrease in indutive effects leads to a decrease in acidity. Therefore an Increasing distance from the -OH group lsads to a decrease in acidity.
From above,
A. Methanol
B. 2-chloropropan-1-ol
C. 2,2-dichloroethanol
D. 2,2-difluoropropan-1-ol
