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2 years ago

What capacitance is needed to store 3μC of charge at a voltage of 120V?

Physics

1 answer:

katrin [286]2 years ago

3 0

Answer:

C = 0.025F

Explanation:

Charge =q=3× $10^{-6}$ C

Voltage=V=120V

Q=CV

C=Q/V

=3× $10^{-6}$ /120

=1/40× $10^{-6}$

C = 0.025F

C=2.5 $10^{-4}$ C 0r 25 × $10^{-3}$ F

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Each step in any energy conversion process will _____.

jeyben [28]

The answer is : lose energy

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3 years ago

Derive the dimension of coefficient of linear expansivity

Reil [10]

Answer:

The SI unit of coefficient of linear expansion can be expressed as °C-1 or °K-1. ... The dimension of coefficient of linear expansion will be M0L0T0K−1.

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3 years ago

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during a crash, the acceleration was less than 30g. Calculate the force on a 70 kg person accelerating at this rate.

Igoryamba

Answer:

less than 20580 N

Explanation:

According to the newton's second law of motion

Force = mass * acceleration

(assuming gravitational acceleration =9.8 m/s2 )

acceleration = 30*9.8 = 294 m/s2

acting Force = 70 * 294

= 20580 N

Since the acceleration was less than 30g , acting force should also be less than 20580 N

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2 years ago

consider the free-body diagram. if you want the box to move, the force applied while dragging must be greater than the

NeTakaya

Answer:

Force of static friction between the two surfaces

Explanation:

When two surfaces come into contact, they exert a force that resist the sliding of the two surfaces. This force is called static friction.

This force is given by the relation

$F_{s}=\mu_{s}\eta$

Where,

μ - coefficient of static friction

η - normal force acting on the body

When a force acts on a body placed on a rough surface, it doesn't do any work if the applied force was less than the force of static friction.

So, in order to move the body, the applied force should be greater than the force of static friction.

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2 years ago

The length of a wooden rod is 25.5 cm. What is this length in: (a) millimetres? (b) metres?

larisa86 [58]

Answer:

$(a)255mm \\ (b)0.255m$

Explanation:

$(a)1cm = 10mm \\ 25.5cm = x$

Cross multiply

$1x = 25.5 \times 10 \\ x = 255mm$

$(b)100cm = 1m \\ 25.5cm = x$

cross multiply

$100x = 25.5 \\ \frac{100x}{100} = \frac{25.5}{100} \\ x = 0.255m$

hope this helps

brainliest appreciated

good luck! have a nice day!

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3 years ago

Read 2 more answers