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2 years ago

What capacitance is needed to store 3μC of charge at a voltage of 120V?

Physics

1 answer:

katrin [286]2 years ago

3 0

<u>Answer:</u>

C = 0.025F

<u>Explanation:</u>

Charge =q=3× $10^{-6}$ C

Voltage=V=120V

Q=CV

C=Q/V

=3× $10^{-6}$ /120

=1/40× $10^{-6}$

C = 0.025F

C=2.5 $10^{-4}$ C 0r 25 × $10^{-3}$ F

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