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sergiy2304 [10]
2 years ago
7

What capacitance is needed to store 3μC of charge at a voltage of 120V?

Physics
1 answer:
katrin [286]2 years ago
3 0

<u>Answer:</u>

 C = 0.025F

<u>Explanation:</u>

Charge =q=3×10^{-6}C

Voltage=V=120V

Q=CV

C=Q/V

   =3×10^{-6}/120

   =1/40×10^{-6}

        C = 0.025F

         C=2.5 10^{-4}C  0r  25 ×10^{-3}F

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