Which element has a greater Ist ionization energy, Phosphorus or Fluorine?
2 answers:
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Answer:
Y = 92.5 %
Explanation:
Hello there!
In this case, since the reaction between lead (II) nitrate and potassium bromide is:
Exhibits a 1:2 mole ratio of the former to the later, we can calculate the moles of lead (II) bromide product to figure out the limiting reactant:
Thus, the limiting reactant is the KBr as it yields the fewest moles of PbBr2 product. Afterwards, we calculate the mass of product by using its molar mass:
And the resulting percent yield:
Regards!
Answer: 50.7 grams
Explanation:
To calculate the moles, we use the equation:
a) moles of
The balanced chemical equation is:
is the limiting reagent as it limits the formation of product and
is in excess.
According to stoichiometry :
2 moles of give = 1 mole of
Thus 0.220 moles of give=
of
Mass of
Thus 50.7 g of will be formed.