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charle [14.2K]
4 years ago
7

PLEASE ANSWER WILL GIVE BRAINLIEST What is the pH of a 500mL solution of 0.25M HCI?

Chemistry
2 answers:
Ket [755]4 years ago
5 0

Answer:

0.60

Explanation:

pH = - log[H+]

[HCl] = [H+] = 0.25 M, because HCl is strong acid, so it dissociates completely.

PH = -log[0.25] = 0.60

fomenos4 years ago
5 0

Explanation:

[HCL] = 0.5 M

HCL(aq) -------------> H+(aq) + Cl- (aq)

[H+] = [HCl]

[H+] = 0.25M

pH = -log[H+]

pH = -log( 0.25 )

pH = 0.6

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The density of benzene at 15 ∘C∘C is 0.8787 g/mL. Calculate the mass of 0.1700 LL of benzene at this temperature. Express your a
SVETLANKA909090 [29]

Answer:

Mass of benzene is: 149.3 g

Explanation:

Let's use density to calculate mass.

Density = Mass / Volume

Mass = Density . volume

Be careful, because density is in g/mL and the volume is in L. So let's convert the L to mL: 0.170 L . 1000 mL / 1L = 170 mL

0.8787 g/mL . 170 mL = Mass of benzene

Mass of benzene is: 149.3 g

5 0
3 years ago
How many moles of atoms are in 6.00 g of 13C?
Lyrx [107]

Answer: 0.462 moles

Explanation: 13C indicates an isotope of carbon and its mass number is 13. It means the mass of 1 mol of 13C is 13 gram.

The question asks to calculate the number of atoms present in 6.00 grams of 13C.

To calculate the number of moles we divide the given grams by the mass of 1 mol of the element. The set could be shown easily using dimensional analysis as:

6.00gram(\frac{1mol}{13gram})

= 0.462 moles

So, there will be 0.462 moles of atoms in 6.00 grams of 13C.

4 0
3 years ago
Read 2 more answers
Calculate the pH of a solution in which [OH–] = 4.5 × 10–9M.
posledela

Answer:

5.65 is the pH.

Explanation:

I am assuming that you are asking for confirmation on your answer. The answer is 5.65.

You would do:

[pOH] = -log[OH-]

          = -log[4.5*10^-9]

         equals about 8.3468

To find pH your would subtract the pOH from 14.

14-8.3468 = 5.65 << Rounded to match the answer choices.

7 0
3 years ago
2. Determine the molarity of the NaOH solution in each trial. a. Trial 1 Molarity: b. Trial 2 Molarity: 3. Calculate the average
butalik [34]

Answer:

This question is incomplete

Explanation:

This question is incomplete but...

1) You can calculate the molarity of the NaOH for each trial by following the steps below.

The formula for Molarity (M) is

M = number of moles (n) ÷ volume (V)

where the unit of volume must be in Litres or dm³

The unit of molarity is mol/dm³ or mol/L or molar conc (M)

The final answer must have the unit of molarity

If the number of moles is not provided, look out for the mass of NaOH used and then calculate your number of moles (n) as

n = mass of NaOH used ÷ molar mass of NaOH

Where the atomic mass of sodium (Na) is 23, oxygen (O) is 16 and hydrogen (H) is 1. Hence, molar mass for NaOH is 23 + 16 + 1 = 40 g/mol

n = mass of NaOH used ÷ 40

2) Average Molarity will be (Trial 1 Molarity +Trial 2 Molarity) ÷ 2

Answer must be in mol/dm³ or mol/L or M

3) Label the volumentric flask containing the NaOH solution with the answer gotten from (2) above

3 0
3 years ago
Please Help! Let P and V represent the pressure and volume of Xe(g). If a piston is used to reduce the volume of the gas to V/2
Elza [17]

1) 2P

2) Average speed does not change

Explanation:

1)

To solve the first part of the problem, we can use Boyle's Law, which states that:

"For a fixed mass of an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"

Mathematically:

pV=const.

where

p is the pressure of the gas

V is its volume

For the Xe gas in this problem we can write

p_1 V_1 = p_2 V_2

where:

p_1 = P is the initial pressure

V_1=V is the initial volume

V_2=\frac{V}{2} is the final volume

Solving for p2, we find the final pressure:

p_2=\frac{P V_1}{V_2}=\frac{pV}{V/2}=2P

So, the pressure has doubled.

2)

The average speed of the atoms/molecules in the gas is given by the formula

v_{rms}=\sqrt{\frac{3RT}{M}}

where

R is the gas constant

T is the absolute temperature (in Kelvin) of the gas

M is the molar mass of the gas

v_{rms} is known as rms speed of the particles in the gas

From the formula, we see that the speed of the atoms in the gas depends only on the temperature of the gas.

In the Xe(g) gas in this problem, the temperature is kept constant; therefore, since nothing changes in the formula, this means that the average speed also does not change.

8 0
4 years ago
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