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3 years ago

According to the Kinetic Molecular Theory, the absolute temperature of a gas is directly related to average molecular kinetic

Chemistry

2 answers:

astra-53 [7]3 years ago

7 0

Answer;

-energy

According to the Kinetic Molecular Theory, the absolute temperature of a gas is directly related to average molecular kinetic energy.

Explanation;

Kinetic molecular theory is a theory that explains that the particles of a gas are in constant random motion, exhibiting perfectly elastic collisions.
This theory may be explained using Boyle's and Charles's law. Such that the average kinetic energy of a given particles of a gas is directly proportion to the absolute temperature.

Alekssandra [29.7K]3 years ago

6 0

Answer: The correct answer is Option D.

Explanation:

Average kinetic energy is defined as the average of kinetic energies of all the particles in a system. It is a measure of temperature. The chemical equation used to calculate average kinetic energy is given as:

$K=\frac{3RT}{2N_A}$

where,

K = average kinetic energy

R = Gas constant

$N_A$ = Avogadro's number

T = temperature of the system

Average kinetic energy of the system is directly proportional to the temperature of the system. Thus, if temperature increases, the average kinetic energy also increases and vice-versa.

From the above information, it is concluded that the correct answer is Option D.

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Determine the number of representative particles in each of the following:

tia_tia [17]

Answer:

(a) 0.294 mol silver = $1.770 * 10^{23}$

(b) 8.98 * 10-3 mol sodium chloride - $5.407 *10^{23}$

(d) 0.310 mol nitrogen (N2) = $1.866 * 10^{23}$

Explanation:

In one mole there are $6.022 * 10^{23}$ atoms/molecules

(a) 0.294 mol silver = $6.022 * 10^{23} * 0.294 = 1.770 * 10^{23}$

(b) 8.98 * 10-3 mol sodium chloride - $5.407 *10^{23}$

(d) 0.310 mol nitrogen (N2) = $0.310 * 6.022 * 10^{23} = 1.866 * 10^{23}$

3 0

3 years ago

If the accepted value for the mass of an object is 20.0g and the student found that the mass of the object was 20.5g what is the

NikAS [45]

Answer:

Results

The percent error between 20 and 20.5 is 2.5%

Explanation:

Percent Error = | (20.5 − 20) / 20 | × 100 = | (0.5) / 20 | × 100 = | 0.025 | × 100 = 2.5% (three decimal places)Percent Error = 2.5%

3 0

3 years ago

Can you please help me ?

disa [49]

Answer:

6.82 moles of Fe2O3

Explanation:

Step 1:

Determination of the number of mole of in 450g of CO2.

This is illustrated below:

Molar Mass of CO2 = 12 + (2x16) = 44g/mol

Mass of CO2 = 450g

Number of mole of CO2 =.?

Number of mole = Mass/Molar Mass

Number of mole of CO2 = 450/44 = 10.23 moles

Step 2:

Determination of the number of mole of Fe2O3 needed for the reaction. This is illustrated below:

2Fe2O3 + 3C—> 4Fe + 3CO2

From the balanced equation above,

2 moles of Fe2O3 reacted to produce 3 moles of CO2.

Therefore, Xmol of Fe2O3 will react to produce 10.23 moles of CO2 i.e

Xmol of Fe2O3 = (2x10.23)/3

Xmol of Fe2O3 = 6.82 moles

Therefore, 6.82 moles of Fe2O3 is required.

3 0

3 years ago

1.5 moles are present in 60.0 grams of calcium.

Andrew [12]

Answer:

True.

Explanation:

To know which option is correct, let us calculate the number of mole present in 60g of calcium. This is illustrated below:

Mass of Ca = 60g

Molar Mass of Ca = 40g/mol

Number of mole Ca =....?

Number of mole = Mass/Molar Mass

Number of mole of Ca = 60/40

Number of mole Ca = 1.5 moles.

From the calculations made above, we can see that 1.5 moles are present in 60.0 grams of calcium

3 0

3 years ago

A 5.325g sample of methyl benzoate, a compound in perfumes , was found to contain 3.758 g of carbon, 0.316 g of hydrogen, and 1.

Alexxandr [17]

Answer: The empirical and molecular formula of the compound is $C_4H_4O$ and $C_8H_8O_2$ respectively

Explanation:

We are given:

Mass of C = 3.758 g

Mass of H = 0.316 g

Mass of O = 1.251 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{3.758g}{12g/mole}=0.313moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.316g}{1g/mole}=0.316moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.251g}{16g/mole}=0.078moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.078 moles.

For Carbon = $\frac{0.313}{0.078}=4.01\approx 4$

For Hydrogen = $\frac{0.316}{0.078}=4.05\approx 4$

For Oxygen = $\frac{0.078}{0.078}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 4 : 4 : 1

The empirical formula for the given compound is $C_4H_4O$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 130 g/mol

Mass of empirical formula = 68 g/mol

Putting values in above equation, we get:

$n=\frac{130g/mol}{68g/mol}=1.9\approx 2$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(2\times 4)}H_{(2\times 4)}O_{(2\times 2)}=C_8H_8O_2$

Hence, the empirical and molecular formula of the compound is $C_4H_4O$ and $C_8H_8O_2$ respectively

4 0

3 years ago