<span>a. address all components of fitness
</span>According to the exercise principle of balance, a workout should address all components of fitness.
<span>NOT:
</span>b. focus on balance and coordination
<span>c. target specific areas for improvement </span>
<span>d. vary exercise activities over time</span>
Answer:
Average speed: 0.5 m/s. Average velocity: 0
Explanation:
Average speed is given by:
![v=\frac{d}{t}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%7D%7Bt%7D)
where
d is the total distance covered (the length, of one lap of the track, so d = 400 m)
t is the time taken to cover that distance (so, t = 800 s)
Substituting,
![v=\frac{400}{800}=0.5 m/s](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B400%7D%7B800%7D%3D0.5%20m%2Fs)
Instead, average velocity is defined as
![v=\frac{d}{t}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%7D%7Bt%7D)
where this time,
d is the displacement, which is the vector connecting the starting point to the final point of the motion
t is still the time taken (800 s)
However, in this case the walker starts and finishes his trip at the same point: therefore, the displacement is zero (d=0), and this means that the average velocity is zero as well.
As water vapour cools, it changes back into liquid form. drops come together to form 'clouds'? maybe
<h2>
Angular acceleration is 80 rad/s²
</h2><h2>
Number of revolutions undergone is 1.02</h2>
Explanation:
We have equation of motion v = u + at
Initial angular velocity, u = 0 rad/s
Final angular velocity, v = 32 rad/s
Time, t = 0.40 s
Substituting
v = u + at
32 = 0 + a x 0.40
a = 80 rad/s²
Angular acceleration is 80 rad/s²
We have equation of motion s = ut + 0.5 at²
Initial angular velocity, u = 0 rad/s
Angular acceleration, a = 80 rad/s²
Time, t = 0.4 s
Substituting
s = ut + 0.5 at²
s = 0 x 0.4 + 0.5 x 80 x 0.4²
s = 6.4 rad
Angular displacement = 6.4 rad
![\texttt{Number of revolutions = }\frac{6.4}{2\pi}=1.02](https://tex.z-dn.net/?f=%5Ctexttt%7BNumber%20of%20revolutions%20%3D%20%7D%5Cfrac%7B6.4%7D%7B2%5Cpi%7D%3D1.02)
Number of revolutions undergone is 1.02
Answer:
2.0 s, 200 m
Explanation:
Time to hit the ground depends only on height. Since the plane is at the same height, the weight lands at the same time as before, 2.0 s.
Since the plane is going twice as fast, the weight will travel twice as far (ignoring air resistance). So it will travel a horizontal distance of 200 m.