Answer:
do you have to make the right decisions to be a person who has been a member who is not the first time a great person who has a job in a day of his life or
Answer:
The program is given below with appropriate comments for better understanding
Explanation:
#Program
# foot stride = 2.5 feet
# 1 mile = 5280 feet
no_stride_first_min = int(input('Enter the number strides made durng the first minute of jogging: '))
no_stride_last_min = int(input('Enter the number strides made durng the last minute of jogging: '))
avg_stride_one_min = (no_stride_first_min + no_stride_last_min)/2 # calculates the average stride per minute
jogging_duration = float(input('Enter the total time spent jogging in hours and minute: '))
jogging_duration_hours = int(jogging_duration) # gets the hour
jogging_duration_min = jogging_duration - int(jogging_duration) # gets the minute
tot_jogging_duration_min = jogging_duration_hours*60 + jogging_duration_min # calculates total time in minutes
dist_feet = (avg_stride_one_min*2.5)*tot_jogging_duration_min # calculates the total distance in feet
dist_miles = dist_feet/5280 # calculates the total distance in mile
print('Distance traveled in miles = {0:.2f} miles'.format(dist_miles))
Answer:
v=82 m/s
s=116m
Explanation:
a=20t

using condition given at t=0

c=-8
now equation becomes
v=10t²-8
v at t= 3s v=82 m/s
again


now using condition given s=50 at t=0
b=50
now equation becomes

calculating s at t=3s
s=116m
Answer:
Cc= 12.7 lb.sec/ft
Explanation:
Given that
m = 22 lb
g= 32 ft/s²

x= 4.5 in
1 in = 0.083 ft
x= 0.375 ft
Spring constant ,K

K= 58.66 lb/ft
The damper coefficient for critically damped system


Cc= 12.7 lb.sec/ft
Answer:
The value of heat transferred watt per foot length Q = 54.78 Watt per foot length.
Explanation:
Diameter of pipe = 2 in = 0.0508 m
Steam temperature
= 300 F = 422.04 K
Duct temperature
= 70 F = 294.26 K
Emmisivity of surface 1 = 0.79
Emmisivity of surface 2 = 0.276
Net emmisivity of both surfaces ∈ = 0.25
Stefan volazman constant
= 5.67 ×

Heat transfer per foot length is given by
Q = ∈
A (
) ------ (1)
Put all the values in equation (1) , we get
Q = 0.25 × 5.67 ×
× 3.14 × 0.0508 × 1 × (
)
Q = 54.78 Watt per foot.
This is the value of heat transferred watt per foot length.