Answer:
The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.
Explanation:
Answer:
k = 1.91 × 10^-5 N m rad^-1
Workings and Solution to this question can be viewed in the screenshot below:
Answer:
W = - 184.8 kW
Explanation:
Given data:





We know that work is done as
![W = - [ Q + \dor m[h_2 - h_1]]](https://tex.z-dn.net/?f=W%20%3D%20-%20%5B%20Q%20%2B%20%5Cdor%20m%5Bh_2%20-%20h_1%5D%5D)
for
density of air is 1.22 kg/m^3 and 
for 


W = -[14 + 1.708[400-300]]
W = - 184.8 kW
Answer:
The rate of work output = -396.17 kJ/s
Explanation:
Here we have the given parameters
Initial temperature, T₁ = 355°C = 628.15 K
Initial pressure, P₁ = 350 kPa
h₁ = 763.088 kJ/kg
s₁ = 4.287 kJ/(kg·K)
Assuming an isentropic system, from tables, we look for the saturation temperature of saturated air at 4.287 kJ/(kg·K) which is approximately
h₂ = 79.572 kJ/kg
The saturation temperature at the given
T₂ = 79°C
The rate of work output
=
×
×(T₂ - T₁)
Where;
= The specific heat of air at constant pressure = 0.7177 kJ/(kg·K)
= The mass flow rate = 2.0 kg/s
Substituting the values, we have;
= 2.0 × 0.7177 × (79 - 355) = -396.17 kJ/s
= -396.17 kJ/s
Answer:
See explaination
Explanation:
please kindly see attachment for the step by step solution of the given problem.