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Alborosie
3 years ago
14

Before allowing an employee to enter an excavation at least four feet deep in must be tested for oxygen deficiency and toxic fum

es. True or false
Chemistry
2 answers:
DIA [1.3K]3 years ago
6 0

Answer:

The given statement is true.

Explanation:

As one goes deeper to the ground, there would be less availability of air and space for the air to come in. This signifies that the concentration of oxygen on the lower section of the excavation seems to be less in comparison to the upper ground. The deeper ground would also seem to comprise gas and oil that got developed by the millions of years’ procedure. These resources seem to be dangerous and toxic to get close by without gearing protective masks.

shepuryov [24]3 years ago
4 0
The answer to your question is True

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Provide the electronic structure diagram of propene showing all molecular orbitals​
exis [7]

Answer:

Explanation:The pi-molecular orbitals in propene (CH3-CH=CH2) are essentially the ... This central carbon thus provides two p-orbitals – one for each pi bond – and these two different p-orbitals have to be perpendicular, leading to a twisted structure as shown: ... It all comes down to where the location of the electron-deficient carbon  

8 0
3 years ago
Aluminum has a density of 2.7 g/cm3, how much space in cm3 would 81 grams of aluminum occupy? Show steps to answering this equat
Evgesh-ka [11]

Answer:

30 cm³

Explanation:

Step 1: Given data

  • Density of aluminum (ρ): 2.7 g/cm³
  • Mass of aluminum (m): 81 g
  • Volume occupied by aluminum (V): ?

Step 2: Calculate the volume occupied by aluminum

The density of aluminum is equal to its mass divided by its volume.

ρ = m/V

V = m/ρ

V = 81 g / 2.7 g/cm³

V = 30 cm³

4 0
2 years ago
A cube of salt is crushed before being stirred into water.
andrew-mc [135]
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7 0
3 years ago
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Hugh wrote the properties of physical and chemical weathering in the table shown.
Talja [164]

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I am sure that the C one is correct

6 0
3 years ago
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A saturated solution of manganese(II) hydroxide was prepared, and an acid–base titration was performed to determine its KspKsp a
trapecia [35]

Answer:

10.945 x 10^-4

Explanation:

Balanced equation:

Mn(OH)2 +  2 HCl  -->  MnCl2  +  H2O

it takes 2 moles HCL for each mole Mn(OH)2

Next find the molarity of the Mn(OH)2 solution

= (1 mole Mn(OH)2 / 2 mole HCl)  X (0.0020 mole HCl / 1000ml) X (4.86 ml)    

= 4.86 x 10^-3 mole  

this is now dissolved in (70 + 4.86)  =  74.86 ml or 0.07486 L

thus [Mn(OH)2]  =  4.86 x 10^-3 mole / 0.07486 L  =  0.064921 M

Ksp =  [Mn2+][OH-]^2  =  4x^3  =  4(0.064921)^3  = 10.945 x 10^-4

6 0
3 years ago
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