Answer with Explanation:
The capillary rise in 2 parallel plates immersed in a liquid is given by the formula
where
is the surface tension of the liquid
is the contact angle of the liquid
is density of liquid
'g' is acceleratioj due to gravity
'd' is seperation between thje plates
Part a) When the liquid is water:
For water and glass we have
Applying the values we get
Part b) When the liquid is mercury:
For mercury and glass we have
Applying the values we get
The negative sign indicates that there is depression in mercury in the tube.
Answer:
The question is a problem that requires the principles of fracture mechanics.
and we will need this equation below to get the Max. Stress that exist at the tip of an internal crack.
Explanation:
Max Stress, σ = 2σ₀√(α/ρ)
where,
σ₀ = Tensile stress = 190MPa = 1.9x10⁸Pa
α = Length of the cracked surface = (4.5x10⁻²mm)/2 = 2.25x10⁻⁵m
ρ = Radius of curvature of the cracked surface = 5x10⁻⁴mm = 5x10⁻⁷m
Max Stress, σ = 2 x 1.9x10⁸ x (2.25x10⁻⁵/5x10⁻⁷)⁰°⁵
Max Stress, σ = 2 x 1.9x10⁸ x 6.708 Pa
Max Stress, σ = 2549MPa
Hence, the magnitude of the maximum stress that exists at the tip of an internal crack = 2549MPa
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Answer: D. Many more people crossed the mountains and settled between the Appalachians and the Mississippi
Explanation:
It was quite difficult to cross the Appalachian mountains at the time of the American colonies which led to the colonies being confined to the east of it.
This was until the late 1700s when Daniel Boone and a team of explorers heard that a path existed through the Appalachians and had been used by natives for a long time. After discovering this ''gap'' which was then named after an English prince, many more people were able to use it to settle more to the west of the continent.
Answer:
Explanation:
Hello,
In this case by combining the first and second law of thermodynamics for this ideal gas, we can obtain the following expression for the differential of the specific entropy <em>at constant pressure</em>:
Whereas Rg is the specific ideal gas constant for the studied gas; thus, integrating:
We obtain the expression to compute the specific entropy change:
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