3 years ago

A force is a push or pull in A.a circle B.an arc C.a straight line

Engineering

1 answer:

Bingel [31]3 years ago

4 0

Answer:

I think it is B: an arc

Explanation:

hope this helps mark as brainiest

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Convection is a function of temperature to the fourth power. a)-True b)-False

strojnjashka [21]

Answer:

The given statement for temperature and convection is False.

Explanation:

Convection is not a function of temperature to the fourth power but it depends linearly on temperature. the below equation shows the linear relation of heat transfer due to convection and temperature:

Q = $H_{c}A(T_{hot} - T_{cold} )$

Whereas, radiation is a function of temperature to the fourth power.

The Stefan-Boltzmann law gives the relationship between an object's temperature and the amount of radiation it emits. The law is given by:

$Q=\sigma T^{4}$

7 0

3 years ago

Determine the average power, complex power and power factor (including whether it is leading or lagging) for a load circuit whos

Paul [167]

Answer:

Average power = 108.25W

Complex power = 125W

PF = 0.866

Explanation:

Check attachment for step by step instructions.

4 0

3 years ago

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What is the heat flux (W/m2) to an object when subjected to convection heat transfer environment given: 24 °C = the surface temp

xxMikexx [17]

Answer:

attached below

Explanation:

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3 years ago

At a festival, spherical balloons with a radius of 140.cm are to be inflated with hot air and released. The air at the festival

Tpy6a [65]

Answer:

find attached

Explanation:

5 0

3 years ago

The diameter of an extruder barrel = 85 mm and its length = 2.00 m. The screw rotates at 55 rev/min, its channel depth = 8.0 mm,

babunello [35]

Answer:

Qx = 9.10 $9.10^5 \times 10^{-6}$ m³/s

Explanation:

given data

diameter = 85 mm

length = 2 m

depth = 9mm

N = 60 rev/min

pressure p = 11 × $10^6$ Pa

viscosity n = 100 Pas

angle = 18°

so Qd will be

Qd = 0.5 × π² ×D²×dc × sinA × cosA ..............1

put here value and we get

Qd = 0.5 × π² × ( 85 $\times 10^{-3}$ )²× 9 $\times 10^{-3}$ × sin18 × cos18

Qd = 94.305 × $10^{-6}$ m³/s

and

Qb = p × π × D × dc³ × sin²A ÷ 12 × n × L ............2

Qb = 11 × $10^{6}$ × π × 85 $\times 10^{-3}$ × ( 9 $\times 10^{-3}$ )³ × sin²18 ÷ 12 × 100 × 2

Qb = 85.2 × $10^{-6}$ m³/s

so here

volume flow rate Qx = Qd - Qb ..............3

Qx = 94.305 × $10^{-6}$ - 85.2 × $10^{-6}$

Qx = 9.10 $9.10^5 \times 10^{-6}$ m³/s

8 0

3 years ago