Question

Given that f(x) = 2x + 1 and g(x) = the quantity of 3x minus 1, divided by 2 , solve for g(f(3)).

Answer 1

Answer:

10

Step-by-step explanation:

Firstly, find the value of f(3)

⇒ $f(3) = 2(3) + 1$   [sub in 3]

⇒ $f(3) = 7$   [multiply by 2 and add 1]

Now, find g(f(3))

⇒ $g(f(3)) = \frac{3(7) - 1}{2}$   [sub in 7]

⇒ $g(f(3)) = \frac{20}{2}$   [multiply by 3 and subtract 1]

⇒ $g(f(3)) = 10$   [divide by 2]