Answer:
W = - 10.5943 KJ, work is negative because it is carried out by the system towards the surroundings.
Explanation:
heat engine:
∴ Th = 485°C
∴ Tc = 42°C
∴ Qh = 9.75 KJ......heat from hot source
first law:
∴ ΔU = Q + W = 0 .........cyclic process
⇒ Q = - W
∴ Q = Qh + Qc = Qh - (- Qc)
∴ Qc: heat from the cold source ( - )
⇒ Qh - ( - Qc) = - W..............(1)
⇒ Qc/Qh = - Tc/Th...........(2)
from (2):
⇒ Qc = - (Tc/Th)(Qh) = - (42°C/485°C)(9.75 KJ)
⇒ Qc = - 0.8443 KJ
replacing in (1):
⇒ - W = 9.75 KJ - ( - 0.8443 KJ)
⇒ - W = 10.5943 KJ
Answer: B) Ten moles of sodium hydroxide and five moles of hydrogen gas will be produced
Explanation: Got it right on USATestPrep
Answer:
k=3.8
Explanation:
Because the temptuee is more.
The Km is the MIchealis-Menten constant and this represents the affinity of the enzyme to its substrate. The higher the value for Km, the higher is the affinity of the enzyme to a substrate and the greater is the rate of reaction. Hexokinase IV has a higher Km than other hexokinases because it has a higher affinity to hexose substrates.
