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8_murik_8 [283]
4 years ago
12

When sedimentary rock is exposed to heat and pressure,what does it change into?

Chemistry
1 answer:
SIZIF [17.4K]4 years ago
8 0
Metamorphic rocks, because sedimentary rocks are formed from compressed sand, gravel, dirt, etc. and igneous rocks are formed by cooled magma, but of course each type of rock can be formed other ways. so it leaves us with metamorphic.
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What type of air mass most likely located over atlanta and Georgia
LuckyWell [14K]
Answer is: continental tropical <span>type of air mass most likely located over Atlanta and Georgia.
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4 0
3 years ago
What products would form if chlorine gas was bubbled through a solution of sodium bromide?
Misha Larkins [42]
NaCl would form because it’s a single replacement reaction
4 0
3 years ago
1.) The process for converting ammonia to nitric acid involves the conversion of NH3 to
Firdavs [7]

Answer:

a) 1.39 g ; b) O₂ is limiting reactant,  NH₃ is excess reactant; c) 0.7 g

Explanation:

We have the masses of two reactants, so this is a limiting reactant problem.

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.  

MM:        17.03    32.00     30.01

              4NH₃  +  5O₂ ⟶ 4NO + 6H₂O

Mass/g:    1.5        1.85

2. Calculate the moles of each reactant  

\text{moles of NH}_{3} = \text{1.5 g NH}_{3} \times \dfrac{\text{1 mol NH}_{3}}{\text{17.03 g NH}_{3}} = \text{0.0881 mol NH}_{3}\\\\\text{moles of O}_{2} = \text{1.85 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.057 81 mol O}_{2}

3. Calculate the moles of NO we can obtain from each reactant

From NH₃:

The molar ratio is 4 mol NO:4 mol NH₃

\text{Moles of NO} = \text{0.0881 mol NH}_{3} \times \dfrac{\text{4 mol NO}}{\text{4 mol NH}_{3}} = \text{0.0881 mol NO}

From O₂:

The molar ratio is 4 mol NO:5 mol O₂

\text{Moles of NO} =  \text{0.057 81 mol O}_{2}\times \dfrac{\text{4 mol NO}}{\text{5 mol O}_{2}} = \text{0.046 25 mol NO}

4. Identify the limiting and excess reactants

The limiting reactant is O₂ because it gives the smaller amount of NO.

The excess reactant is NH₃.

5. Calculate the mass of NO formed

\text{Mass of NO} = \text{0.046 25 mol NO}\times \dfrac{\text{30.01 g NO}}{\text{1 mol NO}} = \textbf{1.39 g NO}

6. Calculate the moles of NH₃ reacted

The molar ratio is 4 mol NH₃:5 mol O₂

\text{Moles reacted} = \text{0.057 81 mol O}_{2} \times \dfrac{\text{4 mol NH}_{3}}{\text{5 mol O}_{2}} = \text{0.046 25 mol NH}_{3}

7. Calculate the mass of NH₃ reacted

\text{Mass reacted} = \text{0.046 25 mol NH}_{3} \times \dfrac{\text{17.03 g NH}_{3}}{\text{1 mol NH}_{3}} = \text{0.7876 g NH}_{3}

8. Calculate the mass of NH₃ remaining

Mass remaining = original mass – mass reacted = (1.5 - 0.7876) g = 0.7 g NH₃

8 0
3 years ago
Why is the first jar of hydrogen gas collected during preparation discarded
valentina_108 [34]

Answer:

Hydrogen is collected by downward displacement of water as it is less denser than water. Hence it comes out at the surface of water . It is insoluble in water so it does not dissolve in water

7 0
2 years ago
Read 2 more answers
5. A gas has a pressure of 1.26 atm and occupies a volume of 7.40 L. If the gas
marin [14]

Answer:

0.499atm

Explanation:

The formula is

P1/V1 = P2/V2

so:

1.26atm/7.40L = P2/2.93L

then:

(1.26atm/7.40L)*2.93L = P2

= 0.4988918911atm

the answer must have 3 sig figs

8 0
3 years ago
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