Answer:
b
Explanation:
mint plant varieties are crossed to express desirable traits
0.375 L of the NaCl solution contains 0.455 moles (1)
since it was diluted to 1.88 L
then let 1.88 L of solution contain x moles (2)
by combining both (1) and (2)
⇒ (0.345 L) x = (0.455 mol) (1.88 L)
⇒ x = (0.242 mol · L) ÷ (0.345 L)
⇒ x = 0.702 mol
Thus the molarity of the NaCl after being diluted is 0.702 M OR 0.702 mol / L OR 0.702 mol/dm³.
First, let's state the chemical reaction:
We can find the number of moles of Cl2 required to produce 0.0923 moles of AlCl3, doing a rule of three: 3 moles of Cl2 reacted produces 2 moles of AlCl3:
The calculation would be:
And the final step is to convert this number of moles to grams. Remember that the molar mass can be calculated using the periodic table, so the molar mass of Cl2 is 70.8 g/mol, and the conversion is:
The answer is that we need 9.770 grams of Cl2 to produce 0.0923 moles of AlCl3.
Answer:
= 913.84 mL
Explanation:
Using the combined gas laws
P1V1/T1 = P2V2/T2
At standard temperature and pressure. the pressure is 10 kPa, while the temperature is 273 K.
V1 = 80.0 mL
P1 = 109 kPa
T1 = -12.5 + 273 = 260.5 K
P2 = 10 kPa
V2 = ?
T2 = 273 K
Therefore;
V2 = P1V1T2/P2T1
= (109 kPa × 80 mL × 273 K)/(10 kPa× 260.5 K)
<u>= 913.84 mL</u>
