40.0 g ( 1 mole ) --------------- 6.02x10²³ molecules
? ? --------------------------- 2.90x10²² molecules
mass = 2.90x10²² * 40.0 / 6.02x10²³
mass = 1.16x10²⁴ / 6.02x10²³
mass = 1.9269 g
hope this helps!
Answer: The of a solution is M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
= volume of solution in ml
moles of =
Now put all the given values in the formula of molality, we get
pH or pOH is the measure of acidity or alkalinity of a solution.
According to stoichiometry,
1 mole of gives 1 mole of
Thus moles of gives = moles of
Putting in the values:
Thus the of a solution prepared by dissolving 0.0912 g of hydrogen chloride in sufficient pure water to prepare 250.0 ml of solution is M
Answer:
E° = -0.133 V
Explanation:
In the reaction:
X(s) + Y⁺(aq) → X⁺(aq) + Y(s)
<em>1 electron is transferred from X to Y</em>
Now, using Nernst equation:
E° = RT / nF ln K
<em>Where R is gas constant (8.314 J/molK), T is absolute temperature (Usually 298.15K), n are transferred electrons (1, for the reaction), F is faraday constant (96485C/mol) and K is equilibrium constant (5.59x10⁻³)</em>
Replacing:
E° = 8.314 J/molK*298.15K / 96485C/mol*1 ln 5.59x10⁻³
<em>E° = -0.133 V</em>
Answer:
The new volume is 5.92 L, which is approximately 6 L
Explanation:
As the gas temperature increases, the molecules move faster and take less time to reach the walls of the container. This means that the number of crashes per unit of time will be greater. That is, there will be an increase (for an instant) in the pressure inside the container and the volume will increase.
So Charles's Law is one of the gas laws that relates the volume and temperature of a certain amount of gas at constant pressure and says that:
- If the temperature increases the volume increases
- If the temperature decreases the volume decreases
Mathematically this is expressed by:
When you want to study two different states, an initial and a final one of a gas, this law is expressed by:
In this case:
- V1: 8 L
- T1: 473 K
- V2: ?
- T2: 350 K
Replacing:
Solving:
V2=5.92 L
<u><em>The new volume is 5.92 L, which is approximately 6 L</em></u>