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kogti [31]
2 years ago
13

What is the probability of tossing two coins in Irvington bus land on heads?

Mathematics
1 answer:
d1i1m1o1n [39]2 years ago
6 0
  • Sample space = {TT, HH, TH, HT} where T is tail and H is head.
  • Number of outcomes = 4
  • The probability of getting two heads on tossing two coins
  • =  (\frac{1}{4}  \times 100)\% \\  = 25\%

<u>Answer</u><u>:</u>

<u>D)</u><u> </u><u>2</u><u>5</u><u>%</u>

Hope you could understand.

If you have any query, feel free to ask.

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Free_Kalibri [48]

Answer:

The answer to the question provided is

\frac{9}{5}

Step-by-step explanation:

T

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3 years ago
What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?
DENIUS [597]

Answer:

i. 9

ii. 14

iii. 405

iv. \frac{n(n-3)}{2}

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

\frac{n(n-3)}{2}

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = \frac{6(6-3)}{2}

                                   = \frac{18}{2}

                                   = 9

The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = \frac{7(7-3)}{2}

                                   = \frac{28}{2}

                                   = 14

The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = \frac{30(30-3)}{2}

                                          = \frac{810}{2}

                                         = 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = \frac{n(n-3)}{2}

The number of diagonals in a n-gon is \frac{n(n-3)}{2}

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Answer:

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Step-by-step explanation:

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X^2 +3x - 18 is the answer
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