Hello,
tan t /(sec t -cos t)= sin t/(cos t *(1/cos t -cos t))
=sin t/(cos t*(1-cos ²t)/cos t))
=sin t/sin² t=1/sin t [or=cosec t.]
Answer:
2b
Step-by-step explanation:
Identify the greatest common factors of 2 and 6, the answer is 2
identify the greatest common between b^2 and b, the answer is b
ao therefore the greatest common factor is 2b.
You might have to ask the question again, i’m jot sure what exactly the question requires
