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kakasveta [241]
2 years ago
9

How to find the centroid of a triangle with coordinates

Mathematics
1 answer:
frosja888 [35]2 years ago
5 0
To find the centroid, follow these steps: Step 1: Identify the coordinates of each vertex. Step 2: Add all the x values from the three vertices coordinates and divide by 3. Step 3: Add all the y values from the three vertices coordinates and divide by 3. Would be your answer
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A statistics instructor likes to assign the material as reading in the textbook and then give a pretest before covering the mate
klio [65]

Answer:

b. The student's scores on the posttest would have a smaller standard deviation.

Step-by-step explanation:

The first test is taken before the material is covered in class so we expect the standard deviation to be high because not everyone's scores would be lying close to the mean. Equal number of students mastered most, some or almost none of the material from reading the textbook based on the pretest result. this means the data is varying, so the standard deviation is large.

Whereas, after the teacher has taught the material and given the homework, they must have understood most of the material. The test they take after teaching as a post test. The results of the post test would have a smaller standard deviation as most of the students would have scored good. Hence, the student's scores on the posttest would have a smaller standard deviation.

8 0
3 years ago
The square shown has sides of length 7z^5 decimeters. Find its area
VikaD [51]

For this case we have that by definition, the area of a square is given by:

A = l ^ 2

Where:

l: It's the side of the square

We have, according to the statement data, that:

l = 7z ^ 5 \ dm

Then, the area is given by:

A = (7z ^ 5 \ dm) ^ 2

By definition of power properties we have to:

(a ^ n) ^ m = a ^ {n * m}

So:

A = (7z ^ 5 \ dm) ^ 2 = 49z^{5 * 2} \ dm ^ 2 = 49z^{10} \ dm ^ 2

Answer:

The area of the square is: 49z^{10} \ dm ^ 2

6 0
3 years ago
Find the particular solution of the differential equation that satisfies the initial condition f'(x) 4x, f(0) = 5 f(x) =
malfutka [58]

Answer: f(x)=2x^2+5

Step-by-step explanation:

First integrate f'(x) so we can find the funtion f(x):

4\int\limits {x} \, dx =4[\frac{1}{2} x^2]=2x^2+C=f(x)

The initial conditions say that when x = 0, the function equals 5. Let's write that down:

f(0)=5=2(0^2)+C=C

Therefore, the integration constant 'C' must equal 5. This means that our function is:

f(x)=2x^2+5

6 0
2 years ago
Question 1 of 10
kvasek [131]

Given:

A parabola opens up or down and its vertex is at the point (h, v).

To find:

The equation of the parabola.

Solution:

A parabola opens up or down. It means it is a vertical parabola.

The vertex form of a vertical parabola is

y=a(x-h)^2+k             ...(i)

Where, a is constant and (h,k) is vertex.

The vertex of given parabola is at point (h,v). Putting h=h and k=v in (i), we get

y=a(x-h)^2+v

The required equation of the parabola is y=a(x-h)^2+v.

Therefore, the correct option is A.

4 0
2 years ago
Read 2 more answers
Help please! 15 points
Yanka [14]

Answer:

the answer is 23. even tho it says he had 30 at the time you must subtract 7 because thats what he started with. hope i could help! :D

Step-by-step explanation:

7 0
2 years ago
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