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eimsori [14]
2 years ago
9

What type of chemical reaction occurs in fireworks

Chemistry
2 answers:
krek1111 [17]2 years ago
6 0
combustion and oxidation.
PSYCHO15rus [73]2 years ago
3 0

Answer:

combustion or/and oxidation

Explanation:

You might be interested in
Is a 93.3% solution dilute or concentrated?<br><br><br> Dilute<br><br><br> Concentrated
oksano4ka [1.4K]

Answer:

<u><em></em></u>

  • <u><em>Concentrated</em></u>

Explanation:

Concentration measures the amount of solute in a solution. There are many expressions of concentration. Some of then are percentage (mass/mass, volume/mass, volume/volume), molarity, molality, mole fraction, among others.

When a solution has a high concentration it is said that it is <em>concentrated; </em>when a solution has a low concentration is is said that is is diluted.

Concentrated solutions expressed in percentage typically have about 80 - 90% (or more) of solute.

Diluted solutions expressed in percentage, tipylcally have about 10% - 20% or less.

But they are not fixed limits. You might say that a 85% solution is concentrated. Acids at 75 % sure are concentrated.

Hence, a 93.3% solution is concentrated, definitely.

3 0
3 years ago
if you are asked to help the laboratory assistant in separating the mixture which method will you see?​
FromTheMoon [43]

Answer:

use secondary data. the normal method to use

3 0
3 years ago
What volume would 7.83 X 10^3 moles of Nitrogen gas occupy?
Kay [80]

Answer:

29.232 l

Explanation:

6.023x10^23 mole of nitrogen =22.4 l

7.83×10^23 mole of nitrogen =

22.4/(6.023×10^23)×7.83×10^23

=29.232 l

4 0
3 years ago
Which statement is correct?
Harman [31]

Among solids, liquids, and gases, solids generally have the highest entropy because solid particles are the least mobile, and entropy is inversely related to mobility of particles.
7 0
3 years ago
What is the Kelvin temperature of the air in a tire if the pressure inside the tire is 188 kPa at 32°C. While driving under peri
DENIUS [597]

Answer:

  • <u>414K</u>

Explanation:

The question is not completely clear because some missing parts or grammar (syntax) errors.

Interpreting it, the question is <em>what is the Kelvin temperatue of the air in a tire, when the pressure in the tire has increased to 225 kPa, if the initial conditions of the air inside the tire were 188kPa of pressure and a temperature of 32ºC.</em>

To solve this, you can assume constant volume and use the law of Gay-Lussac for ideal gases:

          \dfrac{P_1}{T_{1}}=\dfrac{P_2}{T_2}

That equation works with absolute temperatures, i.e. Kelvin.

  • 32ºC = 32 + 273.15 K = 305.15K

Then solve for T₂, substitute and compute:

        T_2=P_2\times \dfrac{T_1}{P_{1}}=225kPa\times \dfrac{305.15K}{188kPa}

        T_2=413.90K\approx 414K\longleftarrow answer

8 0
4 years ago
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