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3 years ago

Is a 93.3% solution dilute or concentrated? Dilute Concentrated

Chemistry

1 answer:

oksano4ka [1.4K]3 years ago

3 0

Answer:

<u><em>Concentrated</em></u>

Explanation:

Concentration measures the amount of solute in a solution. There are many expressions of concentration. Some of then are percentage (mass/mass, volume/mass, volume/volume), molarity, molality, mole fraction, among others.

When a solution has a high concentration it is said that it is <em>concentrated; </em>when a solution has a low concentration is is said that is is diluted.

Concentrated solutions expressed in percentage typically have about 80 - 90% (or more) of solute.

Diluted solutions expressed in percentage, tipylcally have about 10% - 20% or less.

But they are not fixed limits. You might say that a 85% solution is concentrated. Acids at 75 % sure are concentrated.

Hence, a 93.3% solution is concentrated, definitely.

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How many atoms are in 1.65 mol of potassium

cluponka [151]

Answer:

<h2>9.93 × 10²³ atoms</h2>

Explanation:

The number of atoms of potassium can be found by using the formula

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 1.65 × 6.02 × 10²³

We have the final answer as

<h3>9.93 × 10²³ atoms</h3>

Hope this helps you

3 0

3 years ago

How many grams of aluminum sulfate: Al2(SO4)3 , would be formed if 250 g of H2SO4 react with aluminum? The reaction is: 2Al + 3H

NikAS [45]

Answer:

290.8 grams of aluminium sulfate (Al2(SO4)3) will be produced.

Explanation:

Step 1: Data given

Mass of H2SO4 = 250 grams

Molar mass H2SO4 = 98.08 g/mol

Step 2: The balanced equation

2Al + 3H2SO4 → Al2(SO4)3 + 3H2

Step 3: Calculate moles H2SO4

Moles H2SO4 = mass H2SO4 / molar mass H2SO4

Moles H2SO4 = 250 grams / 98.08 g/mol

Moles H2SO5 = 2.55 moles

Step 4: Calculate moles Al2(SO4)3

For 2 moles Al we need 3 moles H2SO4 to produce 1 mol Al2(SO4)3 and 3 moles H2

For 2.55 moles H2SO4 we'll have 2.55/3 = 0.85 moles Al2(SO4)3

Step 5: Calculate mass Al2(SO4)3

Mass Al2(SO4)3 = moles Al2(SO4)3 * molar mass

Mass Al2(SO4)3 = 0.85 moles * 342.15 g/mol

Mass Al2(SO4)3 = 290.8 grams

290.8 grams of aluminium sulfate (Al2(SO4)3) will be produced.

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4 years ago

Particle motion in ice is __________than partlice motion in water.

seraphim [82]

Answer:

1. Faster

Explanation:

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3 years ago

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When NEM is added to a purified solution of creatine kinase, Cys 278 is alkylated, but no other Cys residues in the protein are

USPshnik [31]

Answer:

The answer is given below

Explanation:

Cys 278 residue is the only available cysteine which is alkylated by the addition of N-Ethylmaleimide or NEM (alkylating agent). It works by only alkylating the sulfhydryls. In this case, Cys 278 residue is the only one which has exposed cysteine residue.

While the other residues have their sulfhydryls group either involved in the synthesis of disulfide bonds of proteins or their Cys residues are intrinsically placed in the proteins and cannot be alkylated with NEM.

NEM cannot alkylate if its protein is not available in the free form or it is in bounded form. For NEM to alkylate Cys 278, it should be free and should have sulfhydryls available for alkylation.

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4 years ago

The table above shows data collected on five apples while doing field research outside the laboratory. What type of lab equipmen

nalin [4]

D a gram scale would measure grams

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4 years ago

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