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Len [333]
2 years ago
11

A 25 kg lamp is hanging from a rope. What is the tension force being supplied by the rope?

Physics
1 answer:
Elan Coil [88]2 years ago
7 0

The tension force being supplied by the rope is 245 N.

<h3>What is tension force?</h3>
  • Tension force is the force exerted on a rope or cord due to the weight of an object suspended from it.

The tension force on the given rope due to the weight of the lamp hanging from the rope is calculated by applying Newton's second law of motion as shown below;

T = mg

where;

  • m is the mass = 25 kg
  • g is acceleration due to gravity = 9.8 m/s²

T = 25 x 9.8

T = 245 N

Thus, the tension force being supplied by the rope is 245 N.

Learn more about tension force here: brainly.com/question/12797227

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<span>Hello!
KE=1/2MV^2 where M=2000 kg and V=5 m/s .5(2000)*(5^2)=25000 J</span>
4 0
3 years ago
An unstretched spring has a length of 10. centimeters. When the spring is stretched by a force of 16 newtons, its length is incr
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Answer:

The spring constant of this spring  is 200 N/m.

Explanation:

Given:

Original unstretched length of the spring (x₀) = 10 cm =0.10 m [1 cm =0.01 m]

Stretched length of the spring (x₁) = 18 cm = 0.18 cm

Force acting on the spring (F) = 16 N

Spring constant of the spring (k) = ?

First let us find the change in length of the spring or the elongation caused in the spring due to the applied force.

So, Change in length = Final length - Initial length

\Delta x = x_1-x_0=0.18-0.10=0.08\ m

Now, restoring force acting on the spring is directly related to its elongation or compression as:

F=k\Delta x

Rewriting in terms of 'k', we get:

k=\dfrac{F}{\Delta x}

Now, plug in the given values and solve for 'k'. This gives,

k=\frac{16\ N}{0.08\ m}\\\\k=200\ N/m

Therefore, the spring constant of this spring  is 200 N/m.

5 0
3 years ago
A 65-cm segment of conducting wire carries a current of 0.35
algol13
The intensity of the magnetic force exerted on the wire due to the presence of the magnetic field is given by
F=ILB \sin \theta
where
I is the current in the wire
L is the length of the wire
B is the magnetic field intensity
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In our problem, L=65 cm=0.65 m, I=0.35 A and B=1.24 T. The force on the wire is F=0.26 N, therefore we can rearrange the equation to find the sine of the angle:
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