First, it makes your skin feel cooler<span> when it's wet. And when it </span>evaporates<span> it removes some heat. But sweat will only </span>evaporate<span> in an environment where there isn't much</span>water<span> in the air. In a place with high humidity, there're already lots of </span>water<span> molecules in the air. </span>
The equation for work (W) done by an electric field is:
W = qΔV
where q is the magnitude of the charge and ΔV is the potential difference. The question gives you W and q, so plug n' play to find ΔV:
10 = 2ΔV
ΔV = 5
Answer:
It will have aim at a point "below" the insect.
From the insect's point of view, the fish will appear to be shallower than it actually is because a ray of light from the insect to the fish will be bent "towards" the normal when the ray enters the water
Answer:
Time will be 5 sec
And maximum height will be 1200 feet
Explanation:
We have given that initial velocity of the object u = 160 ft/sec'
Function of height 
Take derivative of the distance
We know that first derivative of distance is velocity
So 
At maximum height we know that velocity is zero
So 
t = 5 sec
So it will take 5 sec to reach maximum height
Now maximum height will occur at t = 5 sec
So maximum height = 
The question is incomplete. The complete question is :
Consider a composite cube made of epoxy with fibers aligned along one axis of the cube (the fibers are parallel to four of the twelve cube edges). If the cube can only be loaded in axial tension such that the force is uniformly applied over - and is normal to - a cube face, what is the lowest possible positive length change the cube can experience under this tension? The applied tensile force is 102 KN. The unloaded cube edge length is 56 mm. The glass fibers have an elastic modulus of 200 GPa. The epoxy has an elastic modulus of 38 GPa. The cube is comprised of 18 vol% epoxy (the balancing vol % is glass fiber). Hint: The loading axis is intentionally unspecified. Answer Format: Lowest possible length increase (change of length) under tension.
Solution :
Given :
= 200 GPa

= 38 GPa

Edge length = 56 mm
Cube is loaded in axial tension such that the force is uniformly applied over a cube face.


GPa
Applied stress 

= 32.5 MPa
By Hooke's law



Length change, 

= 0.016 mm