It is well known that bullets fired at Superman simply bounce off his chest. Suppose that a gangster sprays Superman's chest wit
1 answer:
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Answer:
12.97 km
Explanation:
In order to find the resultant displacement, we have to resolve each of the 3 displacements along the x and y direction.
Taking north as positive y direction and east as positive x-direction, we have:
- Displacement 1: 2.00 km to the north
So
- Displacement 2: 60.0° south of east for 7.00 km
So
- Displacement 3: 9.50 km 35.0° north of east
So
So the net displacement along the two directions is:
So, the distance between the initial and final position is equal to the magnitude of the net displacement:
Answer:
M2 = 278.06 kg
Explanation:
We calculate the weight of M1
W=m*g
Where
m: mass (kg)
g: acceleration due to gravity (m/s²)
W₁=288* 9.8= 2822.4 N
Look at the attached graphic
We calculate the x-y components of the weight :
W₁x= 2822.4*sin41° N =1851.66 N
W₁y= 2822.4 *cos41° N = 2130.09 N
We apply Newton's first law for the balance in M1:
Σ Fy=0
Fn-W₁y=0 , Fn: normal force
Fn=W₁y=2130.09N
Friction Force = Ff=μs *Fn = 0.41*2130.09 =873.34 N
Σ Fx=0
T- W₁x- Ff=0
T= 1851.66 + 873.34
T= 1851.66 + 873.34
T=2725 N
We apply Newton's first law for the balance in M2:
Σ Fy=0
T- W₂ =0
W₂ = T = 2725 N
W₂ = M2*g
M2 = W₂/g
M2 = 2725/9.8
M2 = 278.06 kg
