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Elanso [62]
3 years ago
13

Wobble extensions allows the socket to pivot. O True O False

Engineering
1 answer:
Agata [3.3K]3 years ago
4 0
True

(I’m not sure if that’s right a picture below may help with the answer too)

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Technician A says that the connecting rod and main bearing caps should be marked before removing to ensure that they can be inst
Rama09 [41]

Answer:

Technician A

Explanation:

This is because when the dimacations are made, the surface area and length respectively can be maintained to reduce to idea of force which may lead to damage

3 0
2 years ago
In primary processing their are 3 different steps, what are the steps?
Nana76 [90]

Answer:

Primary processing involves cutting, cleaning, packaging, storage and refrigeration of raw foods to ensure that they are not spoilt before they reach the consumer.

8 0
3 years ago
How does the clearance volume affect the efficiency of the Otto cycle?
eduard

Answer:

Explanation:

A smaller clearance volume means a higher compression. A higher compression means better thermal efficiency. However a compression ratio too high might be troublesome, as it can cause accidental ignition of the fuel-air mix. This is the reason why Otto cycle engines have lower compressions that Diesel engines. In a Diesel engine the mix ignites by compression instead of a spark.

7 0
3 years ago
A rocket is launched vertically from rest with a constant thrust until the rocket reaches an altitude of 25 m and the thrust end
hjlf

Answer:

a) v=19.6 m/s

b) H=19.58 m

c) v_{f}=29.57 m/s  

Explanation:

a) Let's calculate the work done by the rocket until the thrust ends.

W=F_{tot}h=(F_{thrust}-mg)h=(35-(2*9.81))*25=384.5 J

But we know the work is equal to change of kinetic energy, so:

W=\Delta K=\frac{1}{2}mv^{2}

v=\sqrt{\frac{2W}{m}}=19.6 m/s

b) Here we have a free fall motion, because there is not external forces acting, that is way we can use the free-fall equations.

v_{f}^{2}=v_{i}^{2}-2gh

At the maximum height the velocity is 0, so v(f) = 0.

0=v_{i}^{2}-2gH

H=\frac{19.6^{2}}{2*9.81}=19.58 m  

c) Here we can evaluate the motion equation between the rocket at 25 m from the ground and the instant before the rocket touch the ground.

Using the same equation of part b)

v_{f}^{2}=v_{i}^{2}-2gh

v_{f}=\sqrt{19.6^{2}-(2*9.81*(-25))}=29.57 m/s

The minus sign of 25 means the zero of the reference system is at the pint when the thrust ends.

I hope it helps you!

6 0
3 years ago
Briefly explain what are the following AIDC technologies for industry automation:
aliya0001 [1]
I believe a is the answer enjoy
3 0
3 years ago
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