Answer:
A pigtail when wiring is technique that is used in connecting a lot of wires together.
Explanation:
A pigtail is a wire that is short in length. It has two ends. One end has a connector while the other end has other wires connected to it.
Pigtail when wiring is the connection of more than one wire in a circuit to another device. Pigtail when wiring helps to extend the length of the wire in a circuit if the wire used it short).
Pigtail when wiring is a technique what helps to keep the circuit organised because it prevents the wires from getting tangled.
Answer:
Engine bearings are lubricated by <u>motor oils</u> constantly supplied in sufficient amounts to the bearings surfaces. Lubricated friction is characterized by the presence of a thin film of the pressurized lubricant
Explanation:
Answer:
The composition of an alloy is 0.75%wt
Explanation:
Let alloy is a hypoeutectoid alloy.
So, we can apply lever rule which is shown below.
We know that 
and 
Given that 
, we have to find 
Thus,
Hence
%wt
Answer:
The following steps should be followed to create the calculated field:
1. Enter AccountTime: (The AccountTime must be enclosed in #). #12/31/2017#-OpenDate in the first empty field.
2. Right-click the field then click properties. This will allow you format the selected field.
3. Rght-click the query tab and click Save. This will allow you save the query
4. Lastly, Close the query.
Answer:
(a) T₂ =747.5 and K= 474.5 °C (b) 330.178 kJ/kg
Explanation:
Solution
T₁ = 35°C = 308
the first step to take is to Use the Table A-17: Ideal gas properties for air:
Now,
At T₁ = 308 K
V₁ = 217.67 + [308-305/310-305] (221.25 -217.67)
So,
V₁ =219.818 kJ/kg
Thus,
Vr₁ = 596 + [308-305/310-305] (572.3 - 596)
= 581.78
so,
Vr₂/Vr₁ = 1/10
Vr₂ =58.178
Applying Table A-17, at Vr₂ = 58.178
Then,
(a) T₂ = 740 + [58.178 - 59.82/57.63 -59.82] (750 -740)
T₂ = 747.5 and K = 474.5 °C
V₂ =544.02 + [58.178 - 59.82/57.63 -59.82] (551.99 - 544.02)
so,
V₂ =549.996 kJ/kg
Hence,
(b) q - w = v₂ -v₁
= 0 -w = 549.996- 219.818
w = 330.178 kJ/kg
