1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
blagie [28]
3 years ago
10

How many moles are represented in 213 grams of sodium bromide , NaBr?

Chemistry
1 answer:
Eduardwww [97]3 years ago
5 0

Answer:

The number of mole represented is 2.07 moles

Explanation:

Using the formula

n = m/Mm

n - mole

m - mass

Mm- molar mass

Since the mass is given to be 213g

So lets calculate the molar mass of sodium bromide (NaBr)

The molar mass of Na = 22.99

Br = 79.904

Molar mass = 22.99+79.904

= 102.894g/mol

Using the formula n = m/Mm

n = 213g/ 102.894g/mol

n = 2.07moles

You might be interested in
If a object has a mass of 10 kilograms, how much does it weigh in newtons?
Len [333]
Depends on where the object is. On earth, moon , or somewhere without any other mass (theoretically). I think you mean how much does weigh on earth. So, the average gravitational acceleration on earth is : 9.83 m/s^2 To find out how much an object weighs, this is the formula : G=m.g where m is mass of the object g is the gravitational acceleration and G is weight. So, G = 10.9,83 = 98,3 N is the answer.
5 0
3 years ago
The Groups 1 and 2 on the periodic table contain what atom type?
Bumek [7]
Non metals
and metals
8 0
3 years ago
Read 2 more answers
Pf3i2 is a nonpolar molecule. based on this information, determine the f−p−f bond angle, the i−p−i bond angle, and the f−p−i bon
Allisa [31]
Welp ur screwed

......................................................................................
6 0
3 years ago
Read 2 more answers
Based on the equation, how many grams of Br2 are required to react completely with 72.4 grams of AlCl3
svlad2 [7]

Answer:  131 g of bromine is required.

Explanation:

The balanced equation will be :

2AlCl_3+3Br_2\rightarrow 2AlBr_3+3Cl_2

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

moles of AlCl_3

\text{Number of moles}=\frac{72.4g}{133g/mol}=0.544moles

According to stoichiometry :

2 moles of AlCl_3 require  = 3 moles of Br_2

Thus 0.544 moles of AlCl_3 require=\frac{3}{2}\times 0.544=0.816moles  of Br_2

Mass of Br_2=moles\times {\text {Molar mass}}=0.816moles\times 160g/mol=131g

Thus 131 g of bromine is required.

5 0
3 years ago
Consider the following intermediate chemical equations.
Degger [83]

Answer:

-1,300 kJ

I don't want to explain it brainly AAAAA

4 0
3 years ago
Other questions:
  • Enter the chemical formula for the cation present in the aqueous solution of AgNO3.
    13·1 answer
  • While a match burns what type of change occurs?
    14·2 answers
  • A sample of a gas originally at 29 °c and 1.25 atm pressure in a 3.0 l container is allowed to contract until the volume is 2.2
    8·1 answer
  • Which element is likely to be the most reactive?
    15·2 answers
  • Two samples of sodium chloride with different masses were decomposed into their constituent elements. One sample produced 1.731.
    7·1 answer
  • Which of the following is true for compounds?
    10·1 answer
  • Where would the gravitational attraction between the earth and moon be the weakest
    6·1 answer
  • There are<br> moles in 1.26 x 1024 particles.
    12·1 answer
  • Why is more dew formed on a grass and not on polished metal surface​
    9·1 answer
  • What is the scientific method and how do you do it
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!