The distance traveled by plane flying at 1200 Km/h for 2.5 hours is 3000 Km.
Velocity is a vector quantity. It has both a direction and a magnitude. Speed is used to calculate the magnitude of velocity. The meter per second is the S.I. unit for this. The units km/h and km/s are additional units. [LT-1] is the dimensional equation for it.
The distance traveled by the object is calculated as the product of the velocity with which it was moving and the time interval for which the distance covered is calculated.
Distance traveled = Velocity × Time
Given in the question
Velocity of the plane = 1200 Km/h
Time Traveled = 2.5 h
Put in the value, we get
Distance traveled = 1200 × 2.5
Distance traveled = 3000 Km
Hence, the distance traveled by plane flying at 1200 Km/h for 2.5 hours is 3000 Km.
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Given: 280 watts power a day
Unknown: KwH=?in 30 days
Solution: 280 watt-hours per day/1000x30 days
.28 x 30=n
Answer:8.4 kwh
Answer:
3.99*10^-3N/C
Explanation:
Using
Ep= kq/r²
Where r = 0.6mm = 0.6*10^-3m
K= 8.9*10^9 and q= 1.6*10^-19
So = 8.9*10^9 * 1.6*10^-19/0.6*10^-3)²
= 3.99*10^-3N/C
Answer:cause they running down a steep hill
Explanation: that's a confusing question
