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Nikolay [14]
3 years ago
10

Determine the density of chunk of lead that has a mass of 1055 grams and a volume of 93.4 cm^3

Chemistry
1 answer:
Bad White [126]3 years ago
7 0
  • Mass=0155g
  • Volume=93.4cm^3

\\ \tt\longmapsto Density=\dfrac{Mass}{Volume}

\\ \tt\longmapsto Density=\dfrac{1055}{93.4}

\\ \tt\longmapsto Density=11.29g/cm^3

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If 125 ml of o2 gas exerts a pressure of 1.0 atm inside a cylinder, what will the pressure be if the cylinder compressed the vol
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<h2>Hello!</h2>

The answer is: The new pressure is 1.67 atm.

<h2>Why?</h2>

From the statement, we know that the temperature remains constant and the gas volume is changing, meaning that the new pressure will be different than the first pressure.

Since the temperature remains constant, we can calculate the new pressure using the Boyle's Law.

The Boyle's Law states that:

P_{1}V_{1}=P_{2}V_{2}

Where,  

P is the pressure of the gas.

V is the volume of the gas.

Then, the given information is:

V_{1}=125ml=0.125L\\P_{1}=1atm\\V_{2}=75ml=0.075L

Remember, 1 L is equal to 1000 mL.

So,

125mL*\frac{1L}{1000mL}=\frac{125mL*1L}{1000mL}=0.125L\\\\75mL*\frac{1L}{1000mL}=\frac{75mL*1L}{1000mL}=0.075L

So, calculating the new volume, we have:

P_{1}V_{1}=P_{2}V_{2}\\\\1atm*0.125L=P_{2}*0.075L\\\\P_{2}=\frac{1atm*0.125L}{0.075l}=1.67atm

Hence, the new pressure is 1.67 atm.

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