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Anastaziya [24]
2 years ago
8

5. Three charges with q = 7.5 x 10-6 C are located as shown, where

Physics
1 answer:
prisoha [69]2 years ago
5 0

F12 = k • q1 • q2 / r12²

F12 = (9 × 10⁹) • (7.5 × 10⁻⁶)² / (0.25)²

F12 = 8.1 N

F13 = k • q1 • q2 / r12²

F12 = (9 × 10⁹) • (7.5 × 10⁻⁶)² / (0.25² + 0.25²)

F12 = 4.05 N

F² = F12² + F13² + 2(F12)(F13) cos θ

F² = (8.1)² + (4.05)² + 2(8.1)(4.05) cos 45°

F = 11.33 N

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Coulomb's law can be expressed as that the electrical force between two charged bodies is directly proportional to the product of the quantity of charge on the bodies and inversely proportional to the square of the separation distance between the two bodies.

As given in the problem two copper spheres are currently 1.2 meters apart.One sphere has a charge of +2.2•10-4 C and the other has a charge of - 8.9•10-4 C.

As per coulomb's law, opposite charges attract each other.

Thus, If one sphere has a charge of +2.2•10-4 C and the other has a charge of -8.9•10-4 C, then the the force between the charged spheres is the force attractive.

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