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klemol [59]
3 years ago
15

which analogy best represents a supersaturated solution? an empty elevator that has a maximum load of 20 people a single person

in an elevator that has a maximum load of 20 people 20 people in an elevator that has a maximum load of 20 people 25 people in an elevator that has a maximum load of 20 people
Chemistry
2 answers:
Elena-2011 [213]3 years ago
8 0

Answer: 25 people in an elevator that has a maximum load of 20 people

Explanation: Supersaturated solution is defined as the solution in which more amount of solute particles is present than the solvent particles.

1. An empty elevator that has a maximum load of 20 people represents a pure solvent in which no solute is dissolved.

2. A single person in an elevator that has a maximum load of 20 people represents an unsaturated solution in which more solute particles can be dissolved in the solvent.

3. 20 people in an elevator that has a maximum load of 20 people. represents a saturated solution in which no more solute particles can be dissolved in the solvent.

4. 25 people in an elevator that has a maximum load of 20 people represents a supersaturated solution in which in which more amount of solute particles is present than the solvent particles.

Goryan [66]3 years ago
8 0

Answer:

The correct answer is <u>25 people in an elevator that has a maximum load of 20 people</u>

Explanation:

Super saturated solution is defined as those solution which contains solute more than the maximum amount of the solute that can be be dissolved into that solution.

The best analogy representing the supersaturated solution from the given options is:

25 people in an elevator that has a maximum load of 20 people. This because the maximum load allowed on the elevator is of 20 but still more than 20 people are in it. Just like solvent holding more amount of solute beyond its dissolving capacity.

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Pressure of the gas inside the container is 662.59 torr.

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The ideal gas law (PV = nRT) connects the macroscopic characteristics of ideal gases. An ideal gas is one in which the particles are both non-repellent and non-attractive to one another (have no volume).

The general law of ideal gas can be applied here: PV is equal to nRT, where P is the gas pressure in atm.

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If P and T are different values and n and V are constants, then

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1 year ago
A 1.0 g sample of propane, C3H8, was burned in calorimeter. The temperature rose from 28.5 0C to 32.0 0C and heat of combustion
tensa zangetsu [6.8K]

Answer:

A 1.0 g sample of propane, C3H8, was burned in the calorimeter.

The temperature rose from 28.5 0C to 32.0 0C and the heat of combustion 10.5 kJ/g.

Calculate the heat capacity of the calorimeter apparatus in kJ/0C

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Heat of combustion = heat capacity of calorimeter * deltaT\\

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The heat of combustion = 10.5kJ/g.

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Substitute these values in the above formula to get the value of heat capacity of the calorimeter.

deltaT =heat  capacity of calorimeter   * (change in temperature)\\10.5kJ/g = heat  capacity of calorimeter * (3.5^oC)\\\\=>heat capacity of calorimeter = \frac{10.5kJ/g}{3.5^oC} \\=>heat capacity of calorimeter = 3.0 kJ/g.^oC

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The heat capacity of the calorimeter is 3.0kJ/g.^oC.

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