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Alenkinab [10]
3 years ago
15

If you burn 46.0 g of hydrogen and produce 411 g of water, how much oxygen reacted?

Chemistry
1 answer:
g100num [7]3 years ago
3 0
The answer is 365 grams because you need to subtract 411 by 46.
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oksano4ka [1.4K]
Na has a +1 charge, and O has a -1 charge.
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3 years ago
I need help on B-I. Please help quickly i have to go on the bus .
lions [1.4K]
Abiotic is the right answer
3 0
3 years ago
When magnesium combines with oxygen, the reaction involves
nikdorinn [45]

Answer:

The correct answer is option c. transfer of electrons from Mg to O.

Explanation:

Hello!

Let's solve this!

When Magnesium (Mg) reacts with oxygen (O), magnesium oxide is formed.

This reaction is spontaneous and occurs with oxidation number +2 of magnesium and oxidation number -2 of oxygen. It is an ionic union, so magnesium transfers its electrons to oxygen.

We conclude that the correct answer is option c. transfer of electrons from Mg to O.

7 0
4 years ago
1) The temperature inside my refrigerator is about 40 Celsius. If I place a balloon in my fridge that initially has a temperatur
viva [34]

Answer:  The volume of the balloon when it is fully cooled by my refrigerator is 0.3 L

Explanation:

To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=0.5L\\T_1=220^oC=(220+273)K=493K\\V_2=?\\T_2=40^oC=(40+273)K=313K

Putting values in above equation, we get:

\frac{0.5}{493}=\frac{V_2}{313}\\\\V_2=0.3

Thus the volume of the balloon when it is fully cooled by my refrigerator is 0.3 L

4 0
3 years ago
You are working in your laboratory and decide to do some cleaning. You find a test tube with some brown substance congealed at t
Anna [14]

Answer:

  • <em>The mystery substance is</em> <u>C. Bromine (Br) </u>

Explanation:

<em>Argon (Ar) </em>is a noble gas. Whose freezing point is -189 °C (very low), thus it cannot be the frozen substance. Also, it is not reactive, thus is would have not reacted with iron. Hence, argon is not the mystery substance.

<em>Scandium (Sc) </em>is a metal from group 3 of the periodic table, thus is will not react with iron. Thus, scandium is not the mystery substance.

Both <em>bromine</em> and <em>iodine</em> are halogens (group 17 of the periodic table).

The freezing point of bromine is −7.2 °C, ​and the freezing point of iodine is 113.7 °C. Thus, both could be solids (frozen) in the lab.

The reactivity of the halogens decrease from top to bottom inside the group. Bromine is above iodine. Then bromine is more reactive than iodine.

Bromine is reactive enough to react with iron. Iodine is not reactive enough to react with iron.

You can find in the internet that bromine vapour over hot iron reacts  producing iron(III) bromide. Also, that bromine vapors are red-brown.

Therefore, <em>the mystery substance is bromine (Br).</em>

7 0
3 years ago
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