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wolverine [178]
3 years ago
14

The number of horns in jackalopes follows the rules for incomplete dominance. alleles are h = 2 horns, h = 0 horns. if a jackalo

pe that has 2 horns is crossed with a jackalope that has no horns, how many horns will their offspring have? give the genotype(s) and phenotype(s) for their offspring.
Biology
1 answer:
USPshnik [31]3 years ago
3 0
Question is as interesting as the animal jackalope.

We ASSUME that incomplete dominance of the number of horns gives rise to 0,1 or 2 horns, where hh=>0, Hh=>1 ("blend" of 0 and 2), and HH=>2 horns.

So if HH crosses with hh, the genotype of the offspring will be Hh, i.e. phenotype Hh=> 1 horn
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Which is the best example of a eukaryote?​
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A

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) Consider a pea plant- it has a gene controlling seed color- yellow Vs green; another gene controlling seed texture-smooth Vs w
lana [24]

Answer:

Yellow smooth  - 9

Yellow wrinkle - 3

Green smooth- 3

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Explanation:

Let the green color of the seed be depicted by "G" and the yellow color of the seed be depicted by "g"

Let the smooth the seed be depicted by "R" and wrinkled seed be depicted by "r"

F1 cross -  

true breeding smooth green plant ( RRGG) and true breeding wrinkled yellow (rrgg)

F1 gamete will be RG, RG, rg, rg

F1 offspring will be RrGg , Thus all F1 offspring will be heterozygous smooth and yellow.  

Thus,  R is dominant over r and g is dominant over G

F2 Generation –  

RrGg x RrGg

Gametes will be RG, Rg, rG, rg

RG         Rg          rG           rg

RG RRGG RRGg RrGG RrGg

Rg RRGg RRgg RrGg Rrgg

rG RrGG RrGg rrGG rrGg

rg RrGg Rrgg rrGg rrgg

R is dominant over r and g is dominant over G

Genotypes are –  

RRGG - 1  (Smooth Green)

RRGg-2  (Smooth yellow)

RrGG-2  (Smooth Green)

RrGg-4  (Smooth yellow)

RRgg- 1  (smooth yellow)

Rrgg – 2  (Smooth yellow)

rrGG – 1  (wrinkled Green)

rrGg – 2  (Wrinkled yellow)

rrgg – 1  (wrinkled yellow)

Yellow smooth  - 9

Yellow wrinkle - 3

Green smooth- 3

Green Wrinkle - 1

4 0
2 years ago
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