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Mariana [72]
2 years ago
15

There are 4 consecutive EVEN integers that have a sum of 268. What are the integers?

Mathematics
1 answer:
eimsori [14]2 years ago
3 0

64 + 66 + 68 + 70

hope this helps!

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Help me with this... ​
marin [14]

i. 171

ii. 162

iii. 297

Solution,

n(U)= 630

n(I)= 333

n(T)= 168

i. Let n(I intersection T ) be X

333 - x + x + 468 - x = 630 \\ or \: 333 + 468 - x = 630 \\ or \: 801 - x = 630 \\ or \:  - x = 630 - 801 \\ or \:  - x =  - 171 \\ x = 171

<h3>ii.n(only I)= n(I) - n(I intersection T)</h3><h3> = 333 - 171</h3><h3> = 162</h3>

<h3>iii. n ( only T)= n( T) - n( I intersection T)</h3><h3> = 468 - 171</h3><h3> = 297</h3>

<h3>Venn- diagram is shown in the attached picture.</h3>

Hope this helps...

Good luck on your assignment...

4 0
4 years ago
What expression is equivalent to -5(x)+(-4)(-3)
azamat

Answer:-25+-12

Step-by-step explanation:so I made x value as 5 so I multiplied -5x5 and it's -25 then I multiplied -4x-7 and that's -12 so the equivalent expression for my way is -25+-12

6 0
3 years ago
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Answer:

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