A mixture of two gases has a total pressure of 5.7 atm . If one gas has a partial pressure of 4.1 atm , what if the partial pres
2 answers:
Answer:
1.6 atm
Explanation:
We are given that total pressure of mixture of two gases=5.7 atm
Partial pressure of one gas=4.1 atm
We have to find the partial pressure of other branch.
We know that Dalton;s law of partial pressure
It states that pressure exerted by mixture of gases is equal to sum of partial pressure exerted by gases in mixture.
Let x bet the pressure exert by other gas
Apply this law
Total pressure=4.1+x
Hence, the partial pressure of other gas=1.6 atm.
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Answer : The percent abundance of the heaviest isotope is, 78 %
Explanation :
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
As we are given that,
Average atomic mass = 48.68 amu
Mass of heaviest-weight isotope = 49.00 amu
Let the percentage abundance of heaviest-weight isotope = x %
Fractional abundance of heaviest-weight isotope =
Mass of lightest-weight isotope = 47.00 amu
Percentage abundance of lightest-weight isotope = 10 %
Fractional abundance of lightest-weight isotope =
Mass of middle-weight isotope = 48.00 amu
Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %
Fractional abundance of middle-weight isotope =
Now put all the given values in above formula, we get:
Therefore, the percent abundance of the heaviest isotope is, 78 %