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amid [387]
4 years ago
6

A mixture of two gases has a total pressure of 5.7 atm . If one gas has a partial pressure of 4.1 atm , what if the partial pres

sure of the other gas ?
Chemistry
2 answers:
Mrrafil [7]4 years ago
6 0
If the two gases has a total pressure of 5.7 atm and one of the gases has a partial pressure of 4.1 the the other one has the pressure of 1.6

Blizzard [7]4 years ago
3 0

Answer:

1.6 atm

Explanation:

We are given that total pressure of mixture of two gases=5.7 atm

Partial pressure of one gas=4.1 atm

We have to find the partial pressure of other branch.

We know that Dalton;s law of partial pressure

It states that pressure exerted by mixture of gases is equal to sum of partial pressure exerted by  gases in mixture.

Let x bet the pressure exert by other gas

Apply this law

Total pressure=4.1+x

5.7=4.1+x

x=5.7-4.1=1.6

Hence, the partial pressure of other gas=1.6 atm.

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A gas company in Massachusetts charges $1.30 for 15.0 ft^3 of natural gas. (a) Convert this rate to dollars per liter of gas. (b
aleksley [76]

Answer:

Explanation:

a ) 15( ft)³ = 15 ( 12 inch )³  = 15 x 12 x 12 x 12 (inch)³ = 25920 (inch)³

=25920( 2.54 cm)³ = 25920 x 2.54 x 2.54 x 2.54 cm³ =424752.7 cc

424752.7/1000 litre = 424.75 liter

424.75 liters cost 1.30 dollars

1 liter costs    1.3/424.75 = 3.06 x 10⁻³ dollars.

So rate

= 3.06 x 10⁻³ dollars/liter

b ) one liter of water takes 0.304 ft³ of gas

2.1 liter will take 0.304 x 2.1 = 0.6384 ft³ of gas

cost = 1.3 x .6384 / 15 = 0.055328 dollar = 55.33 x 10⁻³ dollar.

7 0
3 years ago
A sample of cobalt has a mass of 27 g and a density of 9 g/cm^3. What would be its volume?
8_murik_8 [283]
Given ,

Mass of sample of cobalt = 27 g

density of sample of cobalt = 9g/cm^3

We know that ,

Density = mass of sample/volume of sample

From that relation ,

We can deduce the following as

Volume = mass of sample/density of sample

Hence , required volume of sample of cobalt = 27 g /9 g/cm^3 = 3 cm^3

The volume is \fbox{3cm cube}
3 0
3 years ago
when 46 grams of water are produced how many grams of oxygen must react according to the equation 2h2+o2=2h2o
natka813 [3]

the balanced equation for the formation of water is as follows

2H₂ + O₂ ---> 2H₂O

molar ratio of oxygen to water is 1:2

mass of water produced is - 46 g

therefore the number of moles of water produced - 46 g / 18 g/mol = 2.56 mol

1 mol of oxygen reacts to give 2 mol of water assuming oxygen is the limiting reactant

for 2 mol of water to be produced 1 mol of oxygen has to react

therefore for 2.56 mol of water to be produced - 1/2 x 2.56 mol = 1.28 mol of oxygen should react

mass of oxygen reacted is - 1.28 mol x 32 g/mol = 41.0 g

mass of oxygen that should react is 41 g

8 0
3 years ago
A solution is prepared by dissolving 10.8 g ammonium sulfate in enough water to make 100.0 mL of stock solution. A 10.00 mL samp
kari74 [83]

Answer:NH

+

4

:

0.272

M

SO

2

−

4

:

0.136

M

Explanation:

We can solve this problem using some molarity calculations:

molarity

=

mol solute

L soln

We should convert the given mass of

(NH

4

)

2

SO

4

to moles using its molar mass (calculated to be

132.14

g/mol

):

10.8

g (NH

4

)

2

SO

4

⎛

⎝

1

l

mol (NH

4

)

2

SO

4

132.14

g (NH

4

)

2

SO

4

⎞

⎠

=

0.0817

mol (NH

4

)

2

SO

4

This is the quantity present in

100

mL soln

, so let's calculate the molarity of the solution (converting volume to liters):

molarity

=

0.0817

l

mol (NH

4

)

2

SO

4

0.100

l

L soln

=

0.817

M

10

mL

of this solution is added to

50

mL H

2

O

, which makes a

60

-

mL

total solution.

We can now use the dilution equation

M

1

V

1

=

M

2

V

2

to find the molality of the new,

60

-

mL

solution:

(

0.0817

M

)

(

10

l

mL

)

=

(

M

2

)

(

60

l

mL

)

M

2

=

(

0.817

M

)

(

10

mL

)

60

mL

=

0.136

M

This means that there are

0.136

moles of

(NH

4

)

2

SO

4

per liter of solution.

Let's recognize that

1

mol (NH

4

)

2

SO

4

contains

2

mol NH

+

4

1

mol SO

2

−

4

The concentrations of each ion is thus

(

2

)

(

0.136

M

)

=

0.272

M

NH

+

4

(

1

)

(

0.136

M

)

=

0.136

M

SO

2

−

4

Explanation:

7 0
3 years ago
What does the term normal imply when used in Alkanes?​
arlik [135]

Answer:

The simplest alkanes have their C atoms bonded in a straight chain; these are called normal alkanes. They are named according to the number of C atoms in the chain.

7 0
3 years ago
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