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amid [387]
3 years ago
6

A mixture of two gases has a total pressure of 5.7 atm . If one gas has a partial pressure of 4.1 atm , what if the partial pres

sure of the other gas ?
Chemistry
2 answers:
Mrrafil [7]3 years ago
6 0
If the two gases has a total pressure of 5.7 atm and one of the gases has a partial pressure of 4.1 the the other one has the pressure of 1.6

Blizzard [7]3 years ago
3 0

Answer:

1.6 atm

Explanation:

We are given that total pressure of mixture of two gases=5.7 atm

Partial pressure of one gas=4.1 atm

We have to find the partial pressure of other branch.

We know that Dalton;s law of partial pressure

It states that pressure exerted by mixture of gases is equal to sum of partial pressure exerted by  gases in mixture.

Let x bet the pressure exert by other gas

Apply this law

Total pressure=4.1+x

5.7=4.1+x

x=5.7-4.1=1.6

Hence, the partial pressure of other gas=1.6 atm.

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1-propanol (P1° = 20.9 Torr at 25 °C) and 2-propanol (P2° = 45.2 Torr at 25 °C) form ideal solutions in all proportions. Let x1
jekas [21]

Answer:

y1 = 0.3162

y2 = 0.6838

Explanation:

ok let us begin,

first we would be defining the parameters;

at 25°C;

1-propanol P1° = 20.90 Torr

2-propanol P2° = 45.2 Torr

From Raoults law:

P(1-propanol) = P⁰ × X(1-propanol)

P(1-propanol) = 20.9 torr × 0.45 = 9.405

P(1-propanol) = 9.405 torr

Also P(2-propanol) = P⁰ × X(2-propanol)

P(2-propanol) = 45.2 torr × 0.45

P(2-propanol) = 20.34 torr

but the total pressure = sum of individual pressures

total pressure = 9.405 + 20.34

total pressure = 29.745 torr

given that y1 and y2 represent the mole fraction of each in the vapor phase

y1 = P1 / total pressure

y1 = 9.405/29.745

y1 = 0.3162

Since y1 + y2 = 1

y2 = 1 - y1

∴ y2 = 1 -  0.3162

y2 = 0.6838

cheers, i hope this helps.

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3 years ago
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