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For convenience write RC=D and solve the ODE dV/dt=-V/D which gives
<span>V=Ae^(-t/D) by separating the variables. </span>
<span>When t=0, V=10 and this gives A=10, </span>
<span>when t=2, V=1 giving 1=10e^(-2/D) and you can find D by taking lns of </span>
<span>each side. D=RC, so R=D/C </span>
<span>You should get 2.90X10^5 ohms</span>
To solve this problem it is necessary to apply the concepts related to Gibbs free energy and spontaneity
At constant temperature and pressure, the change in Gibbs free energy is defined as

Where,
H = Entalpy
T = Temperature
S = Entropy
When the temperature is less than that number it is negative meaning it is a spontaneous reaction.
is also always 0 when using single element reactions. In numerical that implies 
At the equation then,






}
Therefore the temperature changes the reaction from non-spontaneous to spontaneous is 600.89K
Answer:
<h2>WHAT IF I HATE PHYSICS ?</h2>
Answer:
The toy car. An object that isn't moving has no momentum
Explanation: